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javascript将list转换成树状结构的实例

* @param {Object} list list集合 */ function listToTree(myId,pId,list){ function exists(list, parentId){ for(var i=0; i<list.length; i++){ if (list[i][myId] == parentId) return true;

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优化一下List<JSONObject> principalUsers = new ArrayList<>(); StringBuffer sb = new StringBuffer(); String principal = specialWorkSignature.getPrincipal(); List<String> principalUserList = Arrays.asList(principal.split(",")); principalUserList.forEach(c -> { sb.append(0).append(","); }); specialWorkSignature.setPrincipalFile(sb.deleteCharAt(sb.length() - 1).toString()); String recipient = specialWorkSignature.getRecipient(); List<String> recipientUserList = Arrays.asList(recipient.split(",")); StringBuffer sc = new StringBuffer(); recipientUserList.forEach(c -> { sc.append(0).append(","); }); specialWorkSignature.setRecipientFile(sc.deleteCharAt(sc.length() - 1).toString());

List<String> principalUserList = Arrays.asList(specialWorkSignature.getPrincipal().split(",")); String principalFile = String.join(",", Collections.nCopies(principalUserList.size(), "0")); ...

import java.util.*;public class Billionaires { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); Map<String, List<Billionaire>> billionairesByCity = new HashMap<>(); for (int i = 0; i < n; i++) { String name = sc.next(); String city = sc.next(); long fortune = sc.nextLong(); Billionaire billionaire = new Billionaire(name, city, fortune); if (!billionairesByCity.containsKey(city)) { billionairesByCity.put(city, new ArrayList<>()); } billionairesByCity.get(city).add(billionaire); } int m = sc.nextInt(); int k = sc.nextInt(); for (int i = 0; i < k; i++) { int day = sc.nextInt(); String name = sc.next(); String city = sc.next(); List<Billionaire> billionaires = billionairesByCity.get(city); for (Billionaire billionaire : billionaires) { if (billionaire.name.equals(name)) { billionaire.addTravel(day); break; } } } List<String> cities = new ArrayList<>(billionairesByCity.keySet()); Collections.sort(cities); for (String city : cities) { List<Billionaire> billionaires = billionairesByCity.get(city); Map<Integer, Long> wealthByDay = new HashMap<>(); for (Billionaire billionaire : billionaires) { for (int day : billionaire.travels) { wealthByDay.put(day, wealthByDay.getOrDefault(day, 0L) + billionaire.fortune); } } int maxDays = 0; for (int day : wealthByDay.keySet()) { long wealth = wealthByDay.get(day); for (int i = day + 1; i <= m; i++) { long futureWealth = wealthByDay.getOrDefault(i, 0L); if (futureWealth > wealth) { break; } if (i - day > maxDays) { maxDays = i - day; } } } if (maxDays > 0) { System.out.println(city + " " + maxDays); } } } static class Billionaire { String name; String city; long fortune; List<Integer> travels = new ArrayList<>(); public Billionaire(String name, String city, long fortune) { this.name = name; this.city = city; this.fortune = fortune; } public void addTravel(int day) { travels.add(day); } }}的计算复杂度是多少

该程序的计算复杂度是 O(nklogk)，其中 n 是亿万富翁的数量，k 是每个亿万富翁旅行的次数的最大值，m 是最大旅行天数。这是由于程序需要对亿万富翁按照城市进行分组，然后对于每个城市，需要计算出每个亿万富翁在每...

集合创建RDD Spark会将集合中的数据拷贝到集群上去，形成一个分布式的数据集合，也就是一个RDD。相当于是，集合中的部分数据会到一个节点上，而另一部分数据会到其他节点上。然后就可以用并行的方式来操作这个分布式数据集合，即RDD。 ArrayList<Integer> list = new ArrayList<Integer>(); list.add(1); list.add(2); list.add(3); JavaRDD<Integer> rdd = sc.parallelize(list,3);//参数1：Seq集合，必须。参数2：分区数，默认为该Application分配到的资源的CPU核数 Integer sum = rdd.reduce((a, b) -> a + b); System.out.print(sum); 输出：6 reduceByKey 对元素为RDD[K,V]对的RDD中Key相同的元素的Value进行聚合。 List<Tuple2<String,Integer>> list = Arrays.asList(new Tuple2("hive",2),new Tuple2("spark",4),new Tuple2("hive",1)); JavaPairRDD<String, Integer> listRDD = sc.parallelizePairs(list); List<Tuple2<String, Integer>> result = listRDD.reduceByKey((x, y) -> x + y).collect(); 输出： (spark,4) (hive,3) collect ：以数组的形式返回RDD中的所有元素，收集分布在各个worker的数据到driver节点。编程要求根据提示，在右侧编辑器begin-end处补充代码，计算并输出各个学生的总成绩。 ("bj",88)： bj指学生姓名，88指学生成绩。

JavaRDD<Tuple2<String, Integer>> rdd = sc.parallelize(list); // 使用 reduceByKey() 方法将具有相同学生姓名的成绩进行聚合，并计算总成绩 JavaPairRDD<String, Integer> totalScoreRDD = rdd.reduceByKey(...

代码优化 List<DeviceDataShow> list = equDeviceService.deviceAllData(deviceDataSearch); TableDataInfo rspData = new TableDataInfo(); rspData.setCode(200); if (CollectionUtils.isEmpty(list)) { rspData.setRows(new ArrayList<>()); }else{ int start = (deviceDataSearch.getPageNum() - 1) * deviceDataSearch.getPageSize(); if (list.size() >= (deviceDataSearch.getPageNum() * deviceDataSearch.getPageSize())) { rspData.setRows(list.subList(start, deviceDataSearch.getPageSize())); } else { rspData.setRows(list.subList(start,list.size())); } } rspData.setMsg("查询成功"); rspData.setTotal(list.size());

List<DeviceDataShow> list = equDeviceService.deviceAllData(deviceDataSearch); TableDataInfo rspData = new TableDataInfo(); rspData.setCode(HttpServletResponse.SC_OK); if (list == null || list.isEmpty...

static Scanner sc = new Scanner(System.in); static File file=new File("D:\\HeimaIT\\OtherData\\lycode\\javase\\takeawaysystem2\\src\\com\\itheima\\dao\\impl\\ResterauntInfo.txt"); static ArrayList<Resteraunt> resteraunts = new ArrayList<>(); static ArrayList<Menu> orderList = new ArrayList<Menu>(); static ArrayList<Menu> menus = new ArrayList<>(); OrderService orderService=new OrderServiceImpl(); static OrderDaoImpl orderDao = OrderDaoImpl.getInstance(); //单例设计，返回永远的一个resterauntDao对象 static ResterauntDaoImpl resterauntDao=new ResterauntDaoImpl(); private ResterauntDaoImpl() { } static { //加载读取orderDao层的arraylist。用来后面的餐厅加载 ArrayList<ArrayList<Menu>> arrayLists = orderDao.readOrder(); Resteraunt resteraunt = new Resteraunt("家常菜馆1", arrayLists.get(0)); Resteraunt resteraunt2 = new Resteraunt("平价菜馆2", arrayLists.get(1)); Resteraunt resteraunt3 = new Resteraunt("高贵菜馆1", arrayLists.get(2)); Collections.addAll(resteraunts, resteraunt, resteraunt2, resteraunt3); try ( ObjectOutputStream objectOutputStream = new ObjectOutputStream(new FileOutputStream(file)); ){ objectOutputStream.writeObject(resteraunts); } catch (Exception e) { e.printStackTrace(); } } public static ResterauntDaoImpl getInstance(){ return resterauntDao; } public ArrayList<Resteraunt> readResterauntInfo() throws IOException, ClassNotFoundException { ObjectInputStream objectInputStream = new ObjectInputStream(new FileInputStream(file)); Object o = objectInputStream.readObject(); ArrayList<Resteraunt> o1 = (ArrayList<Resteraunt>) o; return o1; }

这段代码是一个餐厅信息管理系统的实现，其中包括了读取餐厅信息、订单信息，获取单例对象等...- 定义了ArrayList<Menu>类型的orderList和menus列表，以及OrderService类型的orderService对象，用于后续的订单管理。

解释一下这段代码：import java.util.*; public class Main{ public static void main(String[] args){ Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int m = sc.nextInt(); int k = sc.nextInt(); List<Integer> ss=new ArrayList<Integer>(); Random rand = new Random(k); for(int i=0;i<n;i++){ ss.add(rand.nextInt(m)); if(i==n-1) System.out.println(ss.get(i)); } } }

5. 通过 sc.nextInt() 方法获取用户输入的三个整数 n、m 和 k。 6. 创建了一个 ArrayList 对象 ss，用于存储随机数。 7. 创建了一个 Random 对象 rand，用于生成随机数。其中 k 是种子值，保证每次运行程序生成的...

scala>val data=sc.parallelize(List(1,2,4,3))

你的第一个问题是关于 Scala 语言的代码，代码中使用了 Spark 的并行化计算框架，将列表 [1,2,4,3] 并行化为一个数据集合 RDD（Resilient Distributed Datasets）。这个 RDD 包含了列表中的元素，并且可以在分布式...

补充下下面代码缺少部分 import java.util.*; class Student implements Comparable <Student> { String name; int age; public Student(String name, int age) { this.age = age; } public int compareTo(Student stu) { // 重写compareTo方法 // 两个Student对象相等，当且仅当二者的age相等 } } public class Main { public static void main(String args[ ]) { List <Student> list = new LinkedList <Student> ( ); Scanner sc = new Scanner(System.in); System.out.println("输入三个学生的信息："); list.add( new Student( sc.next(), sc.nextInt() ) ); list.add( new Student( sc.next(), sc.nextInt() ) ); list.add( new Student( sc.next(), sc.nextInt() ) ); Iterator <Student> it = ; System.out.println("排序前，链表中的数据："); while ( it.hasNext( ) ) { // 是否有下一个元素 Student stu = it.next( ); // 取出下一个元素 System.out.println( "姓名："+ stu.name + "，年龄：" + stu.age ); } //排序 System.out.println("排序后，链表中的数据："); it = list.iterator( ); while ( it.hasNext( ) ) { // 是否有下一个元素 Student stu = it.next( ); // 取出下一个元素 System.out.println( "姓名："+ stu.name + "，年龄：" + stu.age ); } System.out.println("输入要查找的学生信息："); Student stu4 = new Student( sc.next(), sc.nextInt() ); int index = Collections.binarySearch( list, stu4 ); //二分查找 if ( ) System.out.println( stu4.name + "与链表中的" + list.get(index).name + "年龄相同" ); else System.out.println( "链表中的对象，没有一个与" + stu4.name + "年龄相同的" ); } }

list.add(new Student(sc.next(), sc.nextInt())); list.add(new Student(sc.next(), sc.nextInt())); list.add(new Student(sc.next(), sc.nextInt())); Iterator<Student> it = list.iterator(); System.out...

6-2 jmu-Java-05集合-List中指定元素的删除分数 10 作者郑如滨单位集美大学编写以下两个函数 //以空格(单个或多个)为分隔符，将line中的元素抽取出来，放入一个List public static List<String> convertStringToList(String line) //在list中移除掉与str内容相同的元素 public static void remove(List<String> list, String str) 裁判测试程序： public class Main { /covnertStringToList函数代码/ /remove函数代码/ public static void main(String[] args) { Scanner sc = new Scanner(System.in); while(sc.hasNextLine()){ List<String> list = convertStringToList(sc.nextLine()); System.out.println(list); String word = sc.nextLine(); remove(list,word); System.out.println(list); } sc.close(); } } 样例说明：底下展示了4组测试数据。输入样例 1 2 1 2 1 1 1 2 1 11 1 11 1 11 11 2 2 2 1 1 2 3 4 1 3 1 1 输出样例 [1, 2, 1, 2, 1, 1, 1, 2] [2, 2, 2] [11, 1, 11, 1, 11] [1, 1] [2, 2, 2] [2, 2, 2] [1, 2, 3, 4, 1, 3, 1] [2, 3, 4, 3]

List<String> list = convertStringToList(sc.nextLine()); System.out.println(list); String word = sc.nextLine(); remove(list, word); System.out.println(list); } sc.close(); } } 您可以将以上...

private static void searchBySuffix() { Scanner sc = new Scanner(System.in); System.out.print("请输入要检索的目录位置:"); String path = sc.next();//从控制台获取路径 File file = new File(path); if (!file.exists() || !file.isDirectory()) { //判断目录是否存在，是否是目录 System.out.println(path + "(不是有效目录)"); return; } System.out.print("请输入搜索后缀:"); String suffix = sc.next(); String[] suffixArray = suffix.split(",");//获取后缀字符串 //在输入目录下获取所有指定后缀名的文件路径 ArrayList<String> list = FileUtils, listFiles (file, suffixArray); for (Object obj : list) { System.out.println(obj); //将路径打印到控制台 }检测错误并修正

这段代码中有一个错误，方法名中的逗号应该被替换为点号... ArrayList<String> list = FileUtils.listFiles(file, suffixArray); for (Object obj : list) { System.out.println(obj); //将路径打印到控制台 } }

import java.util.*; public class 1450 { static int N, M; static int[] dist; static boolean[] visited; static List<Edge>[] graph; public static void main(String[] args) { Scanner sc = new Scanner(System.in); N = sc.nextInt(); M = sc.nextInt(); dist = new int[N + 1]; visited = new boolean[N + 1]; graph = new List[N + 1]; for (int i = 1; i <= N; i++) { graph[i] = new ArrayList<>(); } for (int i = 0; i < M; i++) { int a = sc.nextInt(); int b = sc.nextInt(); int c = sc.nextInt(); graph[a].add(new Edge(b, c)); graph[b].add(new Edge(a, c)); } int start = sc.nextInt(); int end = sc.nextInt(); int res = dijkstra(start, end); if (res == Integer.MAX_VALUE) { System.out.println("No solution"); } else { System.out.println(res); } } private static int dijkstra(int start, int end) { Arrays.fill(dist, Integer.MAX_VALUE); dist[start] = 0; PriorityQueue<Node> pq = new PriorityQueue<>(); pq.offer(new Node(start, 0)); while (!pq.isEmpty()) { Node curr = pq.poll(); int u = curr.vertex; if (visited[u]) { continue; } visited[u] = true; if (u == end) { return dist[end]; } for (Edge edge : graph[u]) { int v = edge.to; int w = edge.weight; if (!visited[v] && dist[u] != Integer.MAX_VALUE && dist[u] + w < dist[v]) { dist[v] = dist[u] + w; pq.offer(new Node(v, dist[v])); } } } return Integer.MAX_VALUE; } } class Node implements Comparable<Node> { int vertex; int dist; public Node(int vertex, int dist) { this.vertex = vertex; this.dist = dist; } @Override public int compareTo(Node o) { return this.dist - o.dist; } } class Edge { int to; int weight; public Edge(int to, int weight) { this.to = to; this.weight = weight; } }优化该代码

N = sc.nextInt(); M = sc.nextInt(); graph = new int[N + 1][N + 1]; dist1 = new int[N + 1]; dist2 = new int[N + 1]; visited1 = new boolean[N + 1]; visited2 = new boolean[N + 1]; Arrays.fill...

package tiantian; import java.util.; public class Max{ public static void main(String[] args) { System.out.println("请输入:"); Scanner sc=new Scanner(System.in); while(sc.hasNext()) { String a=sc.nextLine(); //System.out.println(a); String b=maxString(a); System.out.println(b); /char[]c=a.toCharArray(); char max=c[0];int index=0; for(int i=0;i<c.length;i++) { if(c[i]>max) max=c[i]; index=i; } System.out.println(max); System.out.println(index); */ } sc.close(); } private static String maxString(String a) { char[] c=a.toCharArray(); char max=c[0]; int index=0; List<Object> list=new ArrayList(); for(int i=0;i<c.length;i++) { list.add(c[i]); } for(int i=0;i<c.length;i++) { if(max<=c[i]) { max=c[i]; index=i; } } int k=0; for(int i=0;i<c.length;i++) { //int k=0; if(c[index]==c[i]) { insertStr(list,i,k); k++; } } String ss=""; for(Object object:list) { ss+=object; } return ss; } private static void insertStr(List<Object> list, int i, int k) { list.add(i+1+k,"(max)"); } } 代码详细解释

if (max <= c[i]) { max = c[i]; index = i; } } int k = 0; for (int i = 0; i < c.length; i++) { // 第三次遍历字符数组，在最大字符后面加上标识 if (c[index] == c[i]) { insertStr(list, i, k); // ...

public class MaxSort { public static void main(String[] args) { Scanner sc=new Scanner(System.in); String str=sc.next(); //ret用来保存当前最长的长度为多少 int ret=0; String str1=""; List<String> list1=new LinkedList<>(); for(int i=0;i<str.length()-1;i++){ if(str.charAt(i)<str.charAt(i+1)){ str1+=str.charAt(i); }else{ str1+=str.charAt(i); list1.add(str1); str1=""; } } //现在说明了i走到了最后一个位置 //i==str.length()-1 if(str.charAt(str.length()-1)>str.charAt(str.length()-2)){ str1+=str.charAt(str.length()-1); list1.add(str1); }else{ list1.add(String.valueOf(str.charAt(str.length()-1))); } String maxString=""; for(int i=0;iret){ maxString=s; ret=s.length(); } } System.out.println(maxString); } }转为C语言

#include <stdio.h> #include <stdlib.h> #include <string.h> int main() { char str[100]; scanf("%s", str); int len = strlen(str); int ret = 0; char str1[100] = ""; char *list1[100]; int count = ...

有一个students表，一个courses表，还有一个连接二者的sc表，请问sc表的实体类中，可以直接用List<Student>映射吗，如果这样，应该如何编写，使用@MantToMany

可以使用@ManyToMany注解来实现将sc表中的课程和学生映射到实体类中的List<Student>属性上。下面是一个示例： java @Entity @Table(name = "sc") public class SC { @Id @GeneratedValue(strategy = ...

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有一个students表，一个courses表，还有一个连接二者的sc表，请问sc表的实体类中，可以直接用List<Student>映射吗，如果这样，应该如何编写，使用@MantToMany

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