m,n,d = A.shape a = A.reshape(m*n,d) a = a.astype(np.float32)

def dec2bin(n, count=8): """returns the binary of integer n, using count number of digits""" return [int((n >> y) & 1) for y in range(count-1, -1, -1)] def dec2binAry(x, bits): mask = np.expand_dims(2np.arange(bits-1,-1,-1),1).T return (np.bitwise_and(np.expand_dims(x,1), mask)!=0).astype(int) def bin2decAry(x): if(x.ndim==1): x = np.expand_dims(x,0) bits = x.shape[1] mask = np.expand_dims(2np.arange(bits-1,-1,-1),1) return x.dot(mask).astype(int) def Morton(A): A = A.astype(int) n = np.ceil(np.log2(np.max(A)+1)).astype(int) x = dec2binAry(A[:,0],n) y = dec2binAry(A[:,1],n) z = dec2binAry(A[:,2],n) m = np.stack((x,y,z),2) m = np.transpose(m,(0, 2, 1)) mcode = np.reshape(m,(A.shape[0],3*n),order='F') return mcode

4. Morton(A): 对输入的三维坐标数组A进行Morton编码。首先确定编码所需的位数n，然后将每个坐标分别转换为n位的二进制数组。最后将这些二进制数组按照一定顺序组合成Morton编码。这些函数可以用于处理二进制...

手写数字识别python代码 (h, w) = img.shape

roi = roi.astype('float32') / 255 result = model.predict(roi) digit = np.argmax(result) cv2.rectangle(img, (x, y), (x+w, y+h), (0, 255, 0), 2) cv2.putText(img, str(digit), (x, y), cv2.FONT_...

mask = torch.from_numpy(mask.reshape(*mask_shape).astype(np.float32))

这是一个关于 PyTorch 的代码问题，我可以回答。这行代码是将一个 numpy 数组转换为 PyTorch 的 tensor，并且将其形状重塑为 mask_shape。最后将其数据类型转换为 float32。

import numpy as np import pickle import math f = open(r'C:\Users\sdnugeo\Desktop\target2.pkl','rb') bi = pickle.load(f) # bi = np.array(bi) data = np.arange(0, 156) print(data) data = data.tolist() # print(data) # 每次抽取1000个数值，共抽取10次 samples = [] c = [] a = 11 r = math.ceil(len(data)/a) print(r) for i in range(a): if len(data) > r : sample = np.random.choice(data, r, replace=False) else: sample = np.random.choice(data, len(data), replace=False) # for s in sample: # data.remove(s) # continue # print(type(sample)) # sample2 = np.array(sample) b = [bi[j] for j in list(sample)] # d = np.array(b) print(type(b)) c.append(b) # c = np.concatenate(c, axis=0) # c = bi[0] print(sample) # print(b) samples.append(sample) for s in sample: data.remove(s) # sample = [s for s in sample if s in data] samples = [np.array(s) for s in samples] samples = np.concatenate(samples, axis=0) c = [np.array(e) for e in c] c = np.concatenate(c, axis=0) # samples = np.array(samples).reshape(-1) print(samples) print(c.shape) 请帮我把这段代码修改成可调用的函数

import numpy as np import pickle import math def sample_data(filepath): f = open(filepath, 'rb') bi = pickle.load(f) data = np.arange(0, 156) data = data.tolist() samples = [] c = [] a = 11 r...

解释这一段代码def auto_whiteBalance(img): b, g, r = cv2.split(img) Y = 0.299 * r + 0.587 * g + 0.114 * b Cr = 0.5 * r - 0.419 * g - 0.081 * b Cb = -0.169 * r - 0.331 * g + 0.5 * b Mr = np.mean(Cr) Mb = np.mean(Cb) Dr = np.var(Cr) Db = np.var(Cb) temp_arry = (np.abs(Cb - (Mb + Db * np.sign(Mb))) < 1.5 * Db) & ( np.abs(Cr - (1.5 * Mr + Dr * np.sign(Mr))) < 1.5 * Dr) RL = Y * temp_arry # 选取候选白点数的最亮10%确定为最终白点，并选择其前10%中的最小亮度值 # L_list = list(np.reshape(RL, (RL.shape[0] * RL.shape[1],)).astype(np.int)) L_list = list(np.reshape(RL, (RL.shape[0] * RL.shape[1],)).astype(int)) hist_list = np.zeros(256) min_val = 0 sum = 0 for val in L_list: hist_list[val] += 1 for l_val in range(255, 0, -1): sum += hist_list[l_val] if sum >= len(L_list) * 0.1: min_val = l_val break # 取最亮的前10%为最终的白点 white_index = RL < min_val RL[white_index] = 0 # 计算选取为白点的每个通道的增益 b[white_index] = 0 g[white_index] = 0 r[white_index] = 0 Y_max = np.max(RL) b_gain = Y_max / (np.sum(b) / np.sum(b > 0)) g_gain = Y_max / (np.sum(g) / np.sum(g > 0)) r_gain = Y_max / (np.sum(r) / np.sum(r > 0)) b, g, r = cv2.split(img) b = b * b_gain g = g * g_gain r = r * r_gain # 溢出处理 b[b > 255] = 255 g[g > 255] = 255 r[r > 255] = 255 res_img = cv2.merge((b, g, r)) return res_img

L_list = list(np.reshape(RL, (RL.shape[0] * RL.shape[1],)).astype(int)) hist_list = np.zeros(256) min_val = 0 sum = 0 for val in L_list: hist_list[val] += 1 for l_val in range(255, 0, -1): sum += ...

优化代码 import cv2 import numpy as np import matplotlib.pyplot as plt from PIL import Image def logic_encrypt(im, x0, mu): xsize, ysize = im.shape # print(xsize, ysize) im = np.array(im).flatten() num = len(im) for i in range(100): x0 = mu * x0 * (1-x0) E = np.zeros(num) E[0] = x0 for i in range(0,num-1): E[i+1] = mu * E[i]* (1-E[i]) E = np.round(E*255).astype(np.uint8) im = np.bitwise_xor(E,im) im = im.reshape(xsize,ysize,-1) im = np.squeeze(im) im = Image.fromarray(im) return im img = cv2.imread('0.jpg',0) img = logic_encrypt(img,0.35,3) f = np.fft.fft2(img) fshift = np.fft.fftshift(f) s = np.log(np.abs(fshift)) plt.imshow(s,'gray') plt.show()

2. 使用位运算代替 np.bitwise_xor()：在逻辑加密的部分，使用了 np.bitwise_xor() 进行位异或运算。你可以尝试使用位运算符 ^ 来替代，因为位运算通常比函数调用更高效。 3. 使用 in-place 操作：在逻辑加密的...

程序提示AttributeError: 'NoneType' object has no attribute 'shape'，优化程序def compute(self): t1 = time.time() depth = np.asarray(self.depth, dtype=np.uint16).T # depth[depth==65535]=0 self.Z = depth / self.depth_scale fx, fy, cx, cy = self.camera_intrinsics X = np.zeros((self.width, self.height)) Y = np.zeros((self.width, self.height)) for i in range(self.width): X[i, :] = np.full(X.shape[1], i) self.X = ((X - cx / 2) * self.Z) / fx for i in range(self.height): Y[:, i] = np.full(Y.shape[0], i) self.Y = ((Y - cy / 2) * self.Z) / fy data_ply = np.zeros((6, self.width * self.height)) data_ply[0] = self.X.T.reshape(-1) data_ply[1] = -self.Y.T.reshape(-1) data_ply[2] = -self.Z.T.reshape(-1) img = np.array(self.rgb, dtype=np.uint8) data_ply[3] = img[:, :, 0:1].reshape(-1) data_ply[4] = img[:, :, 1:2].reshape(-1) data_ply[5] = img[:, :, 2:3].reshape(-1) self.data_ply = data_ply t2 = time.time() print('calcualte 3d point cloud Done.', t2 - t1)

这个错误通常是由于...print('Shape of X:', X.shape) print('Shape of Y:', Y.shape) 这样可以方便地查看 X 和 Y 是否有正确的形状。如果仍然无法解决问题，建议提供更多代码和错误信息，以便更好地排查问题。

import numpy as np import cv2 as cv import matplotlib.pyplot as plt img1 = cv.imread('D:/junzhi/3-7000-10k.png', ) img2 = cv.imread('D:/junzhi/3-7000-10y.png', ) 初始化 AKAZE 探测器 akaze = cv.AKAZE_create() 使用 SIFT 查找关键点和描述 kp1, des1 = akaze.detectAndCompute(img1, None) kp2, des2 = akaze.detectAndCompute(img2, None) BFMatcher 默认参数 bf = cv.BFMatcher() matches = bf.knnMatch(des1, des2, k=2) 旋转测试 good_matches = [] for m,n in matches: if m.distance < 0.75*n.distance: good_matches.append([m]) 画匹配点 img3 = cv.drawMatchesKnn(img1,kp1,img2,kp2,good_matches,None,flags=cv.DrawMatchesFlags_NOT_DRAW_SINGLE_POINTS) #cv.imwrite('matches.png', img3) 选择匹配关键点 ref_matched_kpts = np.float32([kp1[m[0].queryIdx].pt for m in good_matches]).reshape(-1,1,2) sensed_matched_kpts = np.float32([kp2[m[0].trainIdx].pt for m in good_matches]).reshape(-1,1,2) 计算 homography H, status = cv.findHomography(ref_matched_kpts, sensed_matched_kpts, cv.RANSAC,1.0) 变换 warped_image = cv.warpPerspective( img2, H, (img2.shape[1], img2.shape[0])) cv.imwrite('warped.png', warped_image)改进这个程序使输入图像16位，输出图像也为16位

warped_image = (warped_image / 255).astype(np.uint16) * 65535 cv.imwrite('warped.png', warped_image) 这样，输入图像和输出图像都将以16位的位深度进行处理和保存。请注意，这里假设输入图像是在0-65535...

base_model = tf.keras.applications.MobileNet(weights = "imagenet", include_top = False, input_shape = input_shape) base_model.trainable = False inputs = keras.Input(shape = input_shape) x = base_model(inputs, training = False) x = tf.keras.layers.GlobalAveragePooling2D()(x) x = tf.keras.layers.Dropout(0.2)(x) x = tf.keras.layers.Dense(len(categories), activation="softmax")(x) model = keras.Model(inputs = inputs, outputs = x, name="LeafDisease_MobileNet") weight_path = os.path.join(base_dir, 'checkpoints', 'my_checkpoint') model.load_weights(weight_path) img = plt.imread(img_path) img = img / 255. img = cv2.resize(img, (224, 224)) img = img.reshape(-1, 224, 224, 3) img.astype('float32') result = model.predict(img) cate_result = categories[np.argmax(result, axis=1)[0]] return cate_result可以详细解释一下每行代码的作用吗

15. img.astype('float32'): 将图像数据类型转换为float32类型。 16. result = model.predict(img): 对图像进行预测，得到类别概率。 17. cate_result = categories[np.argmax(result, axis=1)[0]]: 取最大...

运行提示numba.core.errors.TypingError: Failed in nopython mode pipeline (step: nopython frontend)，优化程序@numba.jit(nopython=True) def compute(self): # rest of the code t1 = time.time() depth = np.asarray(self.depth, dtype=np.uint16).T self.Z = depth / self.depth_scale fx, fy, cx, cy = self.camera_intrinsics X = np.zeros((self.width, self.height)) Y = np.zeros((self.width, self.height)) for i in numba.prange(self.width): # rest of the code X[i, :] = np.full(X.shape[1], i) self.X = ((X - cx / 2) * self.Z) / fx for i in numba.prange(self.height): # rest of the code Y[:, i] = np.full(Y.shape[0], i) self.Y = ((Y - cy / 2) * self.Z) / fy data_ply = np.zeros((6, self.width * self.height)) data_ply[0] = self.X.T.reshape(-1)[:self.width * self.height] data_ply[1] = -self.Y.T.reshape(-1)[:self.width * self.height] data_ply[2] = -self.Z.T.reshape(-1)[:self.width * self.height] img = np.array(self.rgb, dtype=np.uint8) data_ply[3] = img[:, :, 0:1].reshape(-1)[:self.width * self.height] data_ply[4] = img[:, :, 1:2].reshape(-1)[:self.width * self.height] data_ply[5] = img[:, :, 2:3].reshape(-1)[:self.width * self.height] self.data_ply = data_ply t2 = time.time() print('calcualte 3d point cloud Done.', t2 - t1)

这个错误提示是因为 Numba 在尝试编译...print(type(self.depth)) print(self.depth.shape) 这将输出 self.depth 的类型和形状。你可以在代码中添加类似的语句，以查看变量的类型和形状，从而更好地调试代码。

改写“def truncated_svd(matrix,percent):#percent表示选择的特征值个数占所有特征值个数的比例 #进行奇异值分解 U,sigma,V_T=np.linalg.svd(matrix) m=U.shape[0] n=V_T.shape[0] w=np.zeros((m,n)) for k in range(len(sigma)): #以得到该通道的近似数据矩阵 #逐个累加 w=w+sigma[k]*np.dot(U[:,k].reshape(m,1),V_T[k,:].reshape(1,n)) #如果已经超过设定的比例阈值 if(float(k)/len(sigma)>percent): #将数据值规范到0-255范围内 w[w<0]=0 w[w>255]=255 break #为返回的近似数据矩阵的元素数据类型规范 #为uint8 return np.rint(w).astype("uint8")”

return w.astype("uint8") 这个改写版本的思路是先计算所需要保留的特征值个数，再根据这个特征值个数计算近似矩阵，最后将数据值规范到0-255范围内并将数据类型转换为uint8。这样可以避免循环计算，提高运行...

import numpy as np import pickle f = open(r'C:\Users\sdnugeo\Desktop\target2.pkl','rb') bi = pickle.load(f) # bi = np.array(bi) data = np.arange(0, 156) print(data) data = data.tolist() # print(data) # 每次抽取1000个数值，共抽取10次 samples = [] c = [] for i in range(11): if len(data) > 15: sample = np.random.choice(data, 15, replace=False) else: sample = np.random.choice(data, 6, replace=False) # continue # print(type(sample)) # sample2 = np.array(sample) b = [bi[j] for j in list(sample)] # d = np.array(b) print(type(b)) c.append(b) # c = bi[0] print(sample) print(b) samples.append(sample) # sample = [s for s in sample if s in data] for s in sample: data.remove(s) samples = np.array(samples).reshape(-1) print(samples) print(data)，报错setting an array element with a sequence. The requested array has an inhomogeneous shape after 1 dimensions. The detected shape was (11,) + inhomogeneous part.

samples = [np.array(s) for s in samples] samples = np.concatenate(samples, axis=0) 这样就可以将 samples 转换成一维的 NumPy 数组。另外，你在循环中的最后一次循环中没有把 sample 中的元素移除 ...

dataset = [] for data in np.arange(0, 3, .01): data = math.sin(data * math.pi) dataset.append(data) dataset = np.array(dataset) dataset = dataset.astype('float32') max_value = np.max(dataset) min_value = np.min(dataset) scalar = max_value - min_value dataset = list(map(lambda x: x / scalar, dataset)) def create_dataset(dataset, look_back=3): dataX, dataY = [], [] for i in range(len(dataset) - look_back): a = dataset[i:(i + look_back)] dataX.append(a) dataY.append(dataset[i + look_back]) return np.array(dataX), np.array(dataY)以这段代码为基础写预测正弦函数的RNN代码，绘图真实值和预测值

dataset = dataset.astype('float32') max_value = np.max(dataset) min_value = np.min(dataset) scalar = max_value - min_value dataset = list(map(lambda x: x / scalar, dataset)) # 创建数据集 look_back = ...

import scipy.io as scio import numpy as np from sklearn.decomposition import PCA from sklearn import svm import matplotlib.pyplot as plt import random from sklearn.datasets import make_blobs test_data = scio.loadmat('D:\\python-text\\AllData.mat') train_data = scio.loadmat('D:\\python-text\\label.mat') print(test_data) print(train_data) data2 = np.concatenate((test_data['B021FFT0'], test_data['IR007FFT0']), axis=0) data3 = train_data['label'] print(data2) print(data3) # print(type(data3)) # print(data4) # print(type(data4)) data2 = data2.tolist() data2 = random.sample(data2, 200) data2 = np.array(data2) data3 = data3.tolist() data3 = random.sample(data3, 200) data3 = np.array(data3) # data4,data3= make_blobs(random_state=6) print(data2) print(data3) # print(type(data3)) # 创建一个高斯内核的支持向量机模型 clf = svm.SVC(kernel='rbf', C=1000) clf.fit(data2,data3.reshape(-1)) pca = PCA(n_components=2) # 加载PCA算法，设置降维后主成分数目为2 pca.fit(data2) # 对样本进行降维 data4 = pca.transform(data2) # 以散点图的形式把数据画出来 plt.scatter(data4[:, 0], data4[:, 1], c=data3,s=30, cmap=plt.cm.Paired) # 建立图像坐标 axis = plt.gca() xlim = axis.get_xlim() ylim = axis.get_ylim() # 生成两个等差数列 xx = np.linspace(xlim[0], xlim[1], 30) yy = np.linspace(ylim[0], ylim[1], 30) # print("xx:", xx) # print("yy:", yy) # 生成一个由xx和yy组成的网格 X, Y = np.meshgrid(xx, yy) # print("X:", X) # print("Y:", Y) # 将网格展平成一个二维数组xy xy = np.vstack([X.ravel(), Y.ravel()]).T Z = clf.decision_function(xy).reshape(X.shape) # 画出分界线 axis.contour(X, Y, Z, colors='k', levels=[-1, 0, 1], alpha=0.5, linestyles=['--', '-', '--']) axis.scatter(clf.support_vectors_[:, 0], clf.support_vectors_[:, 1], s=100,linewidth=1, facecolors='none') plt.show()修改一下错误

indices = np.arange(data2.shape[0]) np.random.shuffle(indices) data2 = data2[indices] data3 = data3[indices] # 选择前200个数据作为训练集 data2 = data2[:200] data3 = data3[:200] # 创建一个高斯内核的...

m,n,d = A.shape a = A.reshape(m*n,d) a = a.astype(np.float32)

def Morton(A): A = A.astype(int) n = np.ceil(np.log2(np.max(A)+1)).astype(int) x = dec2binAry(A[:,0],n) y = dec2binAry(A[:,1],n) z = dec2binAry(A[:,2],n) m = np.stack((x,y,z),2) m = np.transpose(m,(0, 2, 1)) mcode = np.reshape(m,(A.shape[0],3*n),order='F')

def Morton(A): A = A.astype(int) n = np.ceil(np.log2(np.max(A)+1)).astype(int) x = dec2binAry(A[:,0],n) y = dec2binAry(A[:,1],n) z = dec2binAry(A[:,2],n) m = np.stack((x,y,z),2) m = np.transpose(m,(0, 2, 1)) mcode = np.reshape(m,(A.shape[0],3*n),order='F') return mcode

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