1!+2!+3!+4!+……+n! n=20,使用c语言
时间: 2023-11-24 17:51:55 浏览: 41
以下是使用C语言计算1!+2!+3!+4!+……+n!的和的代码,其中n=20:
```c
#include <stdio.h>
long long factorial(int n) {
if (n == 0 || n == 1) {
return 1;
} else {
return n * factorial(n - 1);
}
}
int main() {
int n = 20;
long long sum = 0;
for (int i = 1; i <= n; i++) {
sum += factorial(i);
}
printf("1!+2!+3!+...+n! = %lld\n", sum);
return 0;
}
```
相关问题
计算sum=1!+2!+……+n!c语言
计算sum=1!+2!+……+n!的C语言代码如下:
```c
#include <stdio.h>
int main() {
int n, i, j, factorial = 1, sum = 0;
printf("请输入一个正整数n:");
scanf("%d", &n);
for (i = 1; i <= n; i++) {
factorial = 1;
for (j = 1; j <= i; j++) {
factorial *= j;
}
sum += factorial;
}
printf("1!+2!+...+%d! = %d\n", n, sum);
return 0;
}
```
首先,我们需要输入一个正整数n,然后使用两个for循环来计算每个数的阶乘,并将它们相加得到sum。其中,外层循环控制从1到n的数字,内层循环计算每个数字的阶乘。最后输出结果即可。
1!+2!+3!+4!+……+n! n=20
以下是Python计算1!+2!+3!+4!+……+n!的方法:
```python
def factorial_sum(n):
result = 0
factorial = 1
for i in range(1, n+1):
factorial *= i
result += factorial
return result
n = 20
print(factorial_sum(n)) # 输出:2561327494111820313
```
以下是C语言编写函数fun求1!+2!+3!+ …… +n!的和的方法:
```c
#include <stdio.h>
long fun(int n)
{
long sum = 0, factorial = 1;
for (int i = 1; i <= n; i++)
{
factorial *= i;
sum += factorial;
}
return sum;
}
int main()
{
int n;
printf("请输入n的值:");
scanf("%d", &n);
printf("%d的阶乘和为%ld\n", n, fun(n));
return 0;
}
```