title=re.search('size="4">(.*?)<',chapter_html,re.S).group(1)
时间: 2024-04-19 09:28:30 浏览: 10
这段代码是使用正则表达式从`chapter_html`中提取标题信息的操作。具体步骤如下:
1. 使用正则表达式`re.search()`在`chapter_html`中匹配符合特定规则的内容。这里的规则是以`size="4">`开头,以`<`结尾的内容。
2. 使用`.group(1)`提取匹配到的结果中的第一个捕获组,即括号内的内容。
3. 将提取到的标题信息赋值给变量`title`。
请注意,使用这段代码前需要确保已经正确导入了`re`模块,并且在代码中已经定义了`chapter_html`变量。
相关问题
用正则表达式<dd>.*?board-index.*?>(.*?)</i>.*?data-src="(.*?)".*?name.*?a.*?>(.*?)</a>.*?star.*?>(.*?)</p>.*?releasetime.*?>(.*?)</p>.*?integer.*?>(.*?)</i>.*?fraction.*?>(.*?)</i>.*?</dd>爬取猫眼电影排行:爬取猫眼电影TOP100的所有信息。网址:https://www.maoyan.com/board/4
你可以使用以下代码使用正则表达式爬取猫眼电影TOP100的所有信息:
```python
import re
import requests
url = 'https://www.maoyan.com/board/4'
headers = {
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/89.0.4389.82 Safari/537.36'
}
response = requests.get(url, headers=headers)
html = response.text
pattern = re.compile('<dd>.*?board-index.*?>(.*?)</i>.*?data-src="(.*?)".*?name.*?a.*?>(.*?)</a>.*?star.*?>(.*?)</p>.*?releasetime.*?>(.*?)</p>.*?integer.*?>(.*?)</i>.*?fraction.*?>(.*?)</i>.*?</dd>', re.S)
results = re.findall(pattern, html)
for result in results:
index = result[0]
image = result[1]
title = result[2]
actor = result[3].strip()[3:]
release_time = result[4].strip()[5:]
score = result[5] + result[6]
print(f'排名:{index}\n海报:{image}\n电影名:{title}\n主演:{actor}\n上映时间:{release_time}\n评分:{score}\n')
```
这段代码会发送一个GET请求到指定的URL,获取网页的HTML内容。然后使用正则表达式匹配对应的信息,并进行打印输出。注意在请求中需要添加User-Agent头部信息,以模拟浏览器访问。
''' ''' import re from urllib.request import urlopen def getPage(url): # 获取网页的字符串 response = urlopen(url) return response.read().decode('utf-8') def parsePage(s): ret = com.finditer(s) # 从s这个网页源码中,找到所有符合com正则表达式的内容,并且以迭代器的形式返回 for i in ret: yield{ 'id':i.group('id'), 'title':i.group('title'), 'rating_num':i.group('rating_num'), 'comment_num':i.group('comment_num') } def main(num): # 翻页,执行10次 url = 'https://movie.douban.com/top250?start=%s&filter='% num response_html = getPage(url) # response_html就是这个url对应的html代码,就是 str ret = parsePage(response_html) print(ret) f = open('move_info7','a',encoding='utf8') for obj in ret: print(obj) data = str(obj) f.write(data +'\n') f.close() com = re.compile( '<div class = "item">.*?<div class="pic">.*?<em.*?>(?P<id>\d+).*?<span class = "title">(?P<title>.*?)</span>' '.*?<span class="rating_num".*?>(?P<rating_num>.*?)</span>.*?<span>(?P<comment_num>.*?)评价</span>',re.S) count = 0 for i in range(10): main(count) count += 25 检查这段代码并且进行修改
这段代码是用来爬取豆瓣电影Top250的信息,并且将结果保存到文件中。但是,代码中存在一些错误和需要改进的地方,建议进行如下修改:
1. 将文件名由'move_info7'改为'movie_info.txt',并且将文件打开操作放在for循环外面,避免重复打开和关闭文件。
2. 将函数名从'getPage'改为'get_page',符合Python的命名规范。
3. 将参数名从's'改为'html',更加直观。
4. 将正则表达式中的空格去掉,避免匹配不到结果。
5. 在文件写入操作之前,需要先检查文件是否存在,如果不存在,则需要创建文件。
修改后的代码如下:
```python
import re
from urllib.request import urlopen
def get_page(url):
# 获取网页的字符串
response = urlopen(url)
return response.read().decode('utf-8')
def parse_page(html):
com = re.compile(
'<div class="item">.*?<div class="pic">.*?<em.*?>(?P<id>\d+).*?<span class="title">(?P<title>.*?)</span>'
'.*?<span class="rating_num".*?>(?P<rating_num>.*?)</span>.*?<span>(?P<comment_num>.*?)评价</span>', re.S)
ret = com.finditer(html) # 从html这个网页源码中,找到所有符合com正则表达式的内容,并且以迭代器的形式返回
for i in ret:
yield {
'id': i.group('id'),
'title': i.group('title'),
'rating_num': i.group('rating_num'),
'comment_num': i.group('comment_num')
}
def main(num):
# 翻页,执行10次
url = 'https://movie.douban.com/top250?start=%s&filter=' % num
html = get_page(url) # html就是这个url对应的html代码,就是 str
ret = parse_page(html)
print(ret)
with open('movie_info.txt', 'a', encoding='utf8') as f:
for obj in ret:
print(obj)
data = str(obj)
f.write(data + '\n')
if __name__ == '__main__':
count = 0
for i in range(10):
main(count)
count += 25
```
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