用python写一个解3*x**3-2*x**2+9*x-6 = 0方程的代码
时间: 2023-11-26 15:02:57 浏览: 31
```python
# 导入math库
import math
# 定义函数
def solve_equation():
# 定义方程
equation = lambda x: 3 * x ** 3 - 2 * x ** 2 + 9 * x - 6
# 定义误差
error = 1e-6
# 定义初始值
x0 = 0
x1 = 1
# 迭代求解
while abs(x1 - x0) > error:
x0 = x1
x1 = x0 - equation(x0) / (9 * x0 ** 2 - 4 * x0 + 9)
# 返回解
return x1
# 输出解
print(solve_equation())
```
--相关问题--:
1. 什么是lambda函数?
2. 如何在Python
相关问题
帮我写出用python对高次方程3*x**3-2*x**2+9*x-6=0的解的代码
以下是用Python解高次方程3*x**3-2*x**2+9*x-6=0的代码:
a = 3
b = -2
c = 9
d = -6
delta1 = 18*a*b*c-4*b**3*d+b**2*c**2-4*a*c**3-27*a**2*d**2
delta2 = delta1**2-4*(b**2-3*a*c)**3
C = ((delta1+delta2**0.5)/2)**(1/3)
if C == 0:
x1 = x2 = x3 = -(b/(3*a))
else:
x1 = (C-(delta1+delta2**0.5)/2**(1/3)+b/(3*a))
x2 = complex(-(C+(delta1+delta2**0.5)/2**(1/3))/2-b/(3*a), (C-(delta1+delta2**0.5)/2**(1/3))*3**(1/2)/2)
x3 = complex(-(C+(delta1+delta2**0.5)/2**(1/3))/2-b/(3*a), -(C-(delta1+delta2**0.5)/2**(1/3))*3**(1/2)/2)
print("x1=", x1)
print("x2=", x2)
print("x3=", x3)
用python求解2*x**2+3*x+1=0
这是一个数学问题,可以用Python编写程序求解。可以使用sympy库来求解方程,代码如下:
```python
from sympy import *
x = symbols('x')
equation = 2*x**2 + 3*x + 1
solution = solve(equation, x)
print(solution)
```
输出结果为:
```
[-1/2, -1]
```
因此,方程的解为x=-1/2或x=-1。