用Python写一个人机对战的五子棋小游戏，请给出代码

以下是一个简单的五子棋小游戏的Python代码：

import random

board = [['+' for _ in range(15)] for _ in range(15)]

def print_board():
    for row in board:
        print(' '.join(row))

def check_win(player):
    # 检查行
    for row in board:
        if ''.join(row).count(player*5) > 0:
            return True
    # 检查列
    for j in range(15):
        col = [board[i][j] for i in range(15)]
        if ''.join(col).count(player*5) > 0:
            return True
    # 检查对角线
    for i in range(11):
        for j in range(11):
            diagonal = [board[i+k][j+k] for k in range(5)]
            if ''.join(diagonal).count(player*5) > 0:
                return True
    for i in range(11):
        for j in range(4, 15):
            diagonal = [board[i+k][j-k] for k in range(5)]
            if ''.join(diagonal).count(player*5) > 0:
                return True
    return False

def player_move():
    while True:
        x, y = map(int, input("请输入你要落子的坐标，用空格隔开（例如：5 10）：").split())
        if x < 0 or x > 14 or y < 0 or y > 14:
            print("坐标不合法，请重新输入！")
        elif board[x][y] != '+':
            print("该位置已有棋子，请重新输入！")
        else:
            board[x][y] = 'X'
            break

def computer_move():
    while True:
        x, y = random.randint(0, 14), random.randint(0, 14)
        if board[x][y] == '+':
            board[x][y] = 'O'
            break

print("欢迎来到五子棋小游戏！")
print_board()

turn = 0
while True:
    if turn % 2 == 0:
        player_move()
        if check_win('X'):
            print("恭喜你，你赢了！")
            break
    else:
        computer_move()
        if check_win('O'):
            print("很遗憾，你输了！")
            break
    turn += 1
    print_board()