两人轮流掷骰子5次，并将每次掷出的点数累加，5局之后，累计点数最大者获胜，点数相同视为平局。根据此规则实现掷骰子游戏，并算出50盘之后的胜利者(50盘中获胜盘数最多的，即为最终获胜者)。

好的，我可以帮你实现这个掷骰子游戏。以下是代码实现：

import random

class DiceGame:
    def __init__(self):
        self.player1_score = 0
        self.player2_score = 0

    def play_game(self):
        for i in range(5):
            player1_roll = random.randint(1, 6)
            player2_roll = random.randint(1, 6)
            self.player1_score += player1_roll
            self.player2_score += player2_roll
            print(f"Player 1 rolled a {player1_roll}, Player 2 rolled a {player2_roll}")
        print(f"Player 1 score: {self.player1_score}")
        print(f"Player 2 score: {self.player2_score}")

    def play_multiple_games(self, num_games):
        player1_wins = 0
        player2_wins = 0
        for i in range(num_games):
            self.player1_score = 0
            self.player2_score = 0
            self.play_game()
            if self.player1_score > self.player2_score:
                player1_wins += 1
                print("Player 1 wins!")
            elif self.player2_score > self.player1_score:
                player2_wins += 1
                print("Player 2 wins!")
            else:
                print("Tie game!")
            print(f"Player 1 wins: {player1_wins}, Player 2 wins: {player2_wins}")
            print("=====================================")
        if player1_wins > player2_wins:
            print("Player 1 is the winner!")
        elif player2_wins > player1_wins:
            print("Player 2 is the winner!")
        else:
            print("It's a tie!")

上面的代码中，我们定义了一个 `DiceGame` 类，包含了两个玩家的得分。在 `play_game` 方法中，我们让两个玩家轮流掷骰子，每次掷出的点数累加到对应的玩家得分中。在掷完 5 次之后，我们输出两个玩家的得分。在 `play_multiple_games` 方法中，我们实现了多局游戏的逻辑，每局游戏之间输出各自的胜利场次。最后，我们比较两个玩家的胜利场次，输出最终的获胜者。

你可以调用 `play_multiple_games` 方法来运行游戏并输出结果。例如，调用 `play_multiple_games(50)` 将会运行 50 局游戏，然后输出最终的获胜者。