function newPop = crossover(pop, nPop, pCross) newPop = pop; for i = 1:2:nPop if rand < pCross i1 = randi(nPop); i2 = randi(nPop); c = randi(size(pop,2)-1); newPop(i,:) = [pop(i1,1:c), pop(i2,c+1:end)]; newPop(i+1,:) = [pop(i2,1:c), pop(i1,c+1:end)]; end end end function newPop = crossover(pop, nPop, pCross) newPop = pop; for i = 1:2:nPop if rand < pCross i1 = randi(nPop); i2 = randi(nPop); c = randi(size(pop,2)-1)+1; newPop(i,:) = [pop(i1,1:c), pop(i2,c:end)]; newPop(i+1,:) = [pop(i2,1:c), pop(i1,c:end)]; end end end有错误吗
时间: 2023-06-11 09:10:43 浏览: 132
nim-pop3:Nim POP3模块
是的,代码中有一个错误。在第10行和第12行中,变量c的赋值语句应该为:
```c = randi(size(pop,2)-1) + 1;```
这是因为我们需要将c设为一个介于1和size(pop,2)-1之间的随机整数,而randi函数返回的是介于1和size(pop,2)-1之间的随机整数,因此我们需要将其加1才能得到正确的结果。
阅读全文