数字秒表的设计Verliog代码
时间: 2023-11-12 11:06:51 浏览: 56
以下是一个简单的数字秒表设计的 Verilog 代码:
```
module stopwatch(
input clk,
input reset,
input start,
output reg [3:0] ones_place,
output reg [3:0] tens_place,
output reg [3:0] hundreds_place,
output reg [3:0] thousands_place
);
reg [23:0] counter = 0;
always @(posedge clk, posedge reset)
begin
if(reset)
counter <= 0;
else if(start)
counter <= counter + 1;
end
always @(posedge clk)
begin
if(counter == 240000) // 1 second
begin
counter <= 0;
ones_place <= ones_place + 1;
if(ones_place == 10)
begin
ones_place <= 0;
tens_place <= tens_place + 1;
if(tens_place == 10)
begin
tens_place <= 0;
hundreds_place <= hundreds_place + 1;
if(hundreds_place == 10)
begin
hundreds_place <= 0;
thousands_place <= thousands_place + 1;
end
end
end
end
end
endmodule
```
这个设计使用一个计数器来记录经过的时钟周期数,然后每当计数器达到 240000(对应于 1 秒)时,它会将每个数字的位置递增一位。如果计数器达到了最大值,它将被重置为0。当复位信号被置高时,计数器也将被重置为0。