MYSQL 运行失败;SELECT COALESCE(storage_in.in_date, storage_out.out_date) AS date, COALESCE(storage_in.product_name, storage_out.product_name) AS product_name, IFNULL(storage_in.quantity,0) AS IN_, IFNULL(storage_out.quantity,0) AS OUT_, SUM(IFNULL(storage_in.quantity,0) - IFNULL(storage_out.quantity,0)) OVER (PARTITION BY COALESCE(storage_in.in_date,storage_out.out_date), COALESCE(storage_in.product_name,storage_out.product_name) ORDER BY COALESCE(storage_in.in_date, storage_out.out_date)) AS END_ FROM storage_in FULL OUTER JOIN storage_out ON storage_in.product_name=storage_out.product_name AND storage_in.in_date = storage_out.out_date ORDER BY 1,2;
时间: 2024-02-29 15:53:41 浏览: 101
这是一个 SQL 查询语句,用于从两个表中获取产品进出库存信息,并计算每个产品在每个日期的总库存。其中使用了 COALESCE 函数来处理空值,IFNULL 函数来处理 NULL 值。JOIN 条件是产品名称和日期相等,使用了 FULL OUTER JOIN 来保证左右两个表都包含在结果中。最后使用了 OVER 子句来计算每个产品在每个日期的总库存。
从语法上看,这个 SQL 查询语句是正确的,但是可能会受到 MySQL 版本的限制。您可以检查一下 MySQL 的版本以及运行失败的具体原因,然后进行调整。
相关问题
优化成mysql脚本,不使用full outer join;SELECT COALESCE(storage_in.in_date, storage_out.out_date) AS date, COALESCE(storage_in.product_name, storage_out.product_name) AS product_name, IFNULL(storage_in.quantity,0) AS IN_, IFNULL(storage_out.quantity,0) AS OUT_, SUM(IFNULL(storage_in.quantity,0) - IFNULL(storage_out.quantity,0)) OVER (PARTITION BY COALESCE(storage_in.in_date,storage_out.out_date), COALESCE(storage_in.product_name,storage_out.product_name) ORDER BY COALESCE(storage_in.in_date, storage_out.out_date)) AS END_ FROM storage_in FULL OUTER JOIN storage_out ON storage_in.product_name=storage_out.product_name AND storage_in.in_date = storage_out.out_date ORDER BY 1,2;
以下是将 FULL OUTER JOIN 转换为 MySQL 脚本的方法,使用 UNION 和 LEFT JOIN 和 RIGHT JOIN 组合:
```
SELECT COALESCE(storage_in.in_date, storage_out.out_date) AS date,
COALESCE(storage_in.product_name, storage_out.product_name) AS product_name,
IFNULL(storage_in.quantity, 0) AS IN_,
IFNULL(storage_out.quantity, 0) AS OUT_,
SUM(IFNULL(storage_in.quantity, 0) - IFNULL(storage_out.quantity, 0))
OVER (PARTITION BY COALESCE(storage_in.in_date, storage_out.out_date),
COALESCE(storage_in.product_name, storage_out.product_name)
ORDER BY COALESCE(storage_in.in_date, storage_out.out_date)) AS END_
FROM
(SELECT in_date, product_name, quantity FROM storage_in
UNION
SELECT out_date, product_name, 0 FROM storage_out) AS storage
LEFT JOIN storage_in ON storage.in_date = storage_in.in_date
AND storage.product_name = storage_in.product_name
LEFT JOIN storage_out ON storage.out_date = storage_out.out_date
AND storage.product_name = storage_out.product_name
ORDER BY 1, 2;
```
这个脚本使用 UNION 将 storage_in 和 storage_out 表中的数据组合起来,LEFT JOIN 和 RIGHT JOIN 分别连接 storage_in 和 storage_out 表,从而实现 FULL OUTER JOIN 的效果。
coalesce(cc.cust_id_define,lot_hs.customer_id) as cust_id2,
这是一个 SQL 查询语句,其中使用了 COALESCE 函数。COALESCE 函数用于返回参数列表中第一个非 NULL 值,如果参数列表中所有值均为 NULL,则返回 NULL。
在这个查询语句中,cc.cust_id_define 和 lot_hs.customer_id 都是可能为 NULL 的值。使用 COALESCE 函数可以确保 cust_id2 字段不为 NULL,并且优先选取 cc.cust_id_define 的值,如果 cc.cust_id_define 为 NULL,则选取 lot_hs.customer_id 的值。
因此,cust_id2 字段的值将是 cc.cust_id_define 和 lot_hs.customer_id 中的第一个非 NULL 值。
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