Fu1=uSol1==22; Fu1=solve(Fu1,z); fplot(Fu1)限制区间z为(0,20)
时间: 2023-08-10 20:07:14 浏览: 62
好的,以下是MATLAB代码实现:
```matlab
syms t z;
uSol1 = exp(-(t*(1823880169^(1/2) + 43363))/18823200)*(1823880169^(1/2)/506 + 42197/506)*((11*1823880169^(1/2)*(268561*z - 53*1823880169^(1/2)*z + 10*1823880169^(1/2) - 149980850))/(1823880169*(1823880169^(1/2) + 43363)) + (990*exp((t*(1823880169^(1/2) + 43363))/18823200)*(1888087*1823880169^(1/2) + 9119400845))/(1823880169*(1823880169^(1/2) + 43363))) - exp((t*(1823880169^(1/2) - 43363))/18823200)*((5646960*(9119400845*z + 210985*1823880169^(1/2)*z - 12704259*1823880169^(1/2) - 534396889517))/(1823880169*(1823880169^(1/2) - 43363)*(1823880169^(1/2) + 43363)) + (990*exp(-(t*(1823880169^(1/2) - 43363))/18823200)*(1888087*1823880169^(1/2) - 9119400845))/(1823880169*(1823880169^(1/2) - 43363)))*(1823880169^(1/2)/506 - 42197/506) - 22;
Fu1 = uSol1 == 22;
Fu1 = solve(Fu1, z);
fplot(Fu1, [0, 20]);
```
运行该代码,将得到在z为(0,20)区间内的方程的二维曲线。