用c语言贪心算法-dijkstra最短路径代码

好的，下面是使用 Dijkstra 最短路径算法求解带权图中的单源最短路径问题的 C 语言代码实现（假设图用邻接矩阵表示）：

#include <stdio.h>
#include <limits.h>
#define V 9

int minDistance(int dist[], bool sptSet[]) {
    int min = INT_MAX, min_index;

    for (int v = 0; v < V; v++) {
        if (sptSet[v] == false && dist[v] <= min) {
            min = dist[v];
            min_index = v;
        }
    }

    return min_index;
}

void dijkstra(int graph[V][V], int src, int dist[]) {
    bool sptSet[V];

    for (int i = 0; i < V; i++) {
        dist[i] = INT_MAX;
        sptSet[i] = false;
    }

    dist[src] = 0;

    for (int count = 0; count < V - 1; count++) {
        int u = minDistance(dist, sptSet);
        sptSet[u] = true;

        for (int v = 0; v < V; v++) {
            if (!sptSet[v] && graph[u][v] && dist[u] != INT_MAX && dist[u] + graph[u][v] < dist[v]) {
                dist[v] = dist[u] + graph[u][v];
            }
        }
    }
}

int main() {
    int graph[V][V] = {{0, 4, 0, 0, 0, 0, 0, 8, 0},
                       {4, 0, 8, 0, 0, 0, 0, 11, 0},
                       {0, 8, 0, 7, 0, 4, 0, 0, 2},
                       {0, 0, 7, 0, 9, 14, 0, 0, 0},
                       {0, 0, 0, 9, 0, 10, 0, 0, 0},
                       {0, 0, 4, 14, 10, 0, 2, 0, 0},
                       {0, 0, 0, 0, 0, 2, 0, 1, 6},
                       {8, 11, 0, 0, 0, 0, 1, 0, 7},
                       {0, 0, 2, 0, 0, 0, 6, 7, 0}};
    int dist[V];

    dijkstra(graph, 0, dist);

    printf("Vertex \t Distance from Source\n");
    for (int i = 0; i < V; i++) {
        printf("%d \t\t %d\n", i, dist[i]);
    }

    return 0;
}

以上是 Dijkstra 最短路径算法的 C 语言实现，同样需要注意输入数据的格式和边界条件的处理。