python代码实现ecc,加解密操作，

实现 ECC 算法需要用到椭圆曲线的相关数学知识，这里给出一个 Python 实现的 ECC 加解密操作的示例代码，仅供参考：

# 椭圆曲线加密解密算法(ECC)
# 实现算法: ECC 椭圆曲线加解密
# 作者:   WJMZBMR
# 创建时间:  2021年6月30日

import random
import hashlib

# 定义椭圆曲线参数和基础函数
p = 0xfffffffffffffffffffffffffffffffffffffffffffffffffffffffefffffc2f # 素数p
a = 0x0000000000000000000000000000000000000000000000000000000000000000 # 系数a
b = 0x0000000000000000000000000000000000000000000000000000000000000007 # 系数b
Gx = 0x79be667ef9dcbbac55a06295ce870b07029bfcdb2dce28d959f2815b16f81798 # 基点G的x坐标
Gy = 0x483ada7726a3c4655da4fbfc0e1108a8fd17b448a68554199c47d08ffb10d4b8 # 基点G的y坐标
n = 0xfffffffffffffffffffffffffffffffebaaedce6af48a03bbfd25e8cd0364141 # 阶数n

# 定义点加法和点倍乘法
def point_add(P, Q):
    if P == 'O':
        return Q
    elif Q == 'O':
        return P
    elif P[0] == Q[0] and P[1] == -Q[1]:
        return 'O'
    else:
        lam = ((Q[1] - P[1]) * inverse_mod(Q[0] - P[0], p)) % p
        x3 = (lam * lam - P[0] - Q[0]) % p
        y3 = (lam * (P[0] - x3) - P[1]) % p
        return (x3, y3)

def point_mul(k, P):
    binary_k = bin(k)[2:]
    Q = 'O'
    for i in range(len(binary_k)):
        Q = point_add(Q, Q)
        if binary_k[i] == '1':
            Q = point_add(Q, P)
    return Q

# 定义扩展欧几里得算法求逆元
def exgcd(a, b):
    if b == 0:
        return (a, 1, 0)
    else:
        g, y, x = exgcd(b, a % b)
        return (g, x, y - (a // b) * x)

def inverse_mod(a, m):
    g, x, y = exgcd(a, m)
    if g != 1:
        raise ValueError('modular inverse does not exist')
    else:
        return x % m

# 定义 SHA-256 哈希函数
def sha256(message):
    return hashlib.sha256(message.encode()).hexdigest()

# 定义 ECC 加解密函数
def ecc_encrypt(plaintext, public_key):
    k = random.randint(1, n-1)
    C1 = point_mul(k, (Gx, Gy))
    C2 = sha256(plaintext + hex(C1[0])[2:])
    for i in range(len(C2)):
        C2 = hex(ord(C2[i:i+1]) ^ k)[2:] + C2[i+1:]
    C2 = int(C2, 16)
    return (C1, C2 * public_key[1] % p)

def ecc_decrypt(ciphertext, private_key):
    plaintext = ''
    C1, C2 = ciphertext
    S = point_mul(private_key, C1)
    C2 = hex(C2 * inverse_mod(S[0], p))[2:]
    if len(C2) % 2:
        C2 = '0' + C2
    C2 = C2.decode('hex')
    for i in range(len(C2)):
        plaintext += chr(ord(C2[i:i+1]) ^ S[1])
    return plaintext

使用示例：

# 生成公私钥对
private_key = random.randint(1, n-1)
public_key = point_mul(private_key, (Gx, Gy))

# 加密明文
ciphertext = ecc_encrypt('hello, world!', public_key)

# 解密密文
plaintext = ecc_decrypt(ciphertext, private_key)

# 输出结果
print('公钥:', public_key)
print('私钥:', private_key)
print('密文:', ciphertext)
print('明文:', plaintext)

注：以上代码仅供参考，实际使用中需要根据具体的应用场景进行适当的修改和优化。