编写一个应用程序，在窗口输入a，b，c三个数值，实现ax*x+bx+c=0的求解，并最终的求解的结果在窗口显示出来

以下是Java代码实现应用程序，在窗口输入a、b、c三个数值，实现ax*x+bx+c=0的求解，并最终的求解的结果在窗口显示出来：

import javax.swing.*;
import java.awt.*;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;

public class QuadraticEquationSolver extends JFrame implements ActionListener {
    private final JLabel labelA, labelB, labelC, labelResult;
    private final JTextField txtA, txtB, txtC;
    private final JButton btnCalculate, btnReset;

    public QuadraticEquationSolver() {
        setTitle("Quadratic Equation Solver");
        setSize(350, 200);
        setLayout(new GridLayout(4, 2));

        labelA = new JLabel("Enter a:");
        txtA = new JTextField();
        add(labelA);
        add(txtA);

        labelB = new JLabel("Enter b:");
        txtB = new JTextField();
        add(labelB);
        add(txtB);

        labelC = new JLabel("Enter c:");
        txtC = new JTextField();
        add(labelC);
        add(txtC);

        btnCalculate = new JButton("Calculate");
        btnCalculate.addActionListener(this);
        add(btnCalculate);

        btnReset = new JButton("Reset");
        btnReset.addActionListener(this);
        add(btnReset);

        labelResult = new JLabel("", JLabel.CENTER);
        add(labelResult);

        setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        setVisible(true);
    }

    @Override
    public void actionPerformed(ActionEvent e) {
        if (e.getSource() == btnCalculate) {
            try {
                double a = Double.parseDouble(txtA.getText());
                double b = Double.parseDouble(txtB.getText());
                double c = Double.parseDouble(txtC.getText());

                double discriminant = b * b - 4 * a * c;

                if (discriminant < 0) {
                    labelResult.setText("No real roots");
                } else if (discriminant == 0) {
                    double x = -b / (2 * a);
                    labelResult.setText("The root is: " + x);
                } else {
                    double x1 = (-b + Math.sqrt(discriminant)) / (2 * a);
                    double x2 = (-b - Math.sqrt(discriminant)) / (2 * a);
                    labelResult.setText("The roots are: " + x1 + " and " + x2);
                }
            } catch (NumberFormatException ex) {
                labelResult.setText("Invalid input");
            }
        } else if (e.getSource() == btnReset) {
            txtA.setText("");
            txtB.setText("");
            txtC.setText("");
            labelResult.setText("");
        }
    }

    public static void main(String[] args) {
        new QuadraticEquationSolver();
    }
}

该程序使用了 Java 的图形用户界面（GUI），通过继承 JFrame 类并实现 ActionListener 接口来实现用户输入和事件处理。用户可以在窗口中输入 a、b、c 三个数值，然后点击“Calculate”按钮来计算方程的根，并将计算结果显示在窗口中。如果用户需要重新输入值，可以点击“Reset”按钮清空输入框。