设计算法删除单链表中大于mink且小于maxk的所有元素,并释放被删结点的存储空间c语言算法
时间: 2024-03-07 12:50:50 浏览: 24
可以按照以下步骤实现该算法:
1. 定义单链表节点结构体:
```
typedef struct ListNode {
int val;
struct ListNode *next;
} ListNode;
```
2. 定义删除函数,该函数接受单链表的头指针、mink和maxk,返回删除后的单链表的头指针:
```
ListNode* deleteNodes(ListNode* head, int mink, int maxk) {
}
```
3. 初始化一个虚拟头节点dummy,使其next指向头节点head:
```
ListNode* dummy = (ListNode*)malloc(sizeof(ListNode));
dummy->next = head;
```
4. 定义两个指针pre和cur,分别指向虚拟头节点和头节点:
```
ListNode* pre = dummy;
ListNode* cur = head;
```
5. 遍历链表,如果当前节点的值大于等于mink且小于等于maxk,则删除该节点:
```
while (cur != NULL) {
if (cur->val >= mink && cur->val <= maxk) {
pre->next = cur->next;
ListNode* tmp = cur;
cur = cur->next;
free(tmp);
} else {
pre = cur;
cur = cur->next;
}
}
```
6. 释放虚拟头节点的存储空间:
```
ListNode* newHead = dummy->next;
free(dummy);
```
7. 返回删除后的单链表的头指针newHead:
```
return newHead;
```
完整的C语言实现代码如下:
```
typedef struct ListNode {
int val;
struct ListNode *next;
} ListNode;
ListNode* deleteNodes(ListNode* head, int mink, int maxk) {
ListNode* dummy = (ListNode*)malloc(sizeof(ListNode));
dummy->next = head;
ListNode* pre = dummy;
ListNode* cur = head;
while (cur != NULL) {
if (cur->val >= mink && cur->val <= maxk) {
pre->next = cur->next;
ListNode* tmp = cur;
cur = cur->next;
free(tmp);
} else {
pre = cur;
cur = cur->next;
}
}
ListNode* newHead = dummy->next;
free(dummy);
return newHead;
}
```