T=int(input()) for t in range(T): m, n = map(int, input().split()) zd = {} s = map(str, input().split()) s = list(s) book = {} book1 = {} for M in range(m): zd[s[M]] = 0 d = map(float, input().split()) d = list(d) book[M] = d for N in range(n): book1[N] = [] for M in range(m): book1[N].append(book[M][N]) zd = {} for M in range(m): zd[s[M]] = 0 for N in range(n): if book[M][N] == min(book1[N]): zd[s[M]] += 1 zdt = sorted(zd.items(), key=lambda x: (-x[1], x[0])) for i in range(m): print("{} {}".format(zdt[i][0], zdt[i][1]))解释代码
时间: 2023-06-12 17:02:01 浏览: 44
这是一段 Python 代码,用于实现某种算法。具体来说,它通过输入多组数据,每组数据包含一个矩阵和一个字符串列表,会对每个字符串在矩阵中的出现情况进行统计,并输出按照出现次数排序的字符串列表。
具体的代码逻辑如下:
1. 读入测试数据组数 T,并循环遍历每组数据。
2. 读入两个整数 m 和 n,表示矩阵的行数和列数。
3. 初始化一个字典 zd,用于记录每个字符串在整个矩阵中是否出现过。
4. 读入一个字符串列表 s,表示矩阵中所有可能出现的字符串。
5. 初始化两个字典 book 和 book1,分别用于记录矩阵中的值和转置矩阵中的值。
6. 针对每一行数据,将其转化为一个数组,并将该数组存入 book 中。
7. 针对每一列数据,将其转化为一个数组,并将该数组存入 book1 中。
8. 针对每个字符串 s,检查其是否为转置矩阵中对应列的最小值,如果是则将其在字典 zd 中的值设为 1。
9. 将字典 zd 按值从大到小、键字典序从小到大的顺序进行排序,存入列表 zdt 中。
10. 遍历 zdt 列表,输出每个字符串和其在矩阵中出现的次数。
需要注意的是,为了不透露用户的具体需求,代码实现的功能可能与用户可能预期的不同,因此用户应当自己理解和解释代码的具体功能和用途。
相关问题
约瑟夫环改错class Node: def __init__(self,data): self.data=data self.next=Noneclass linklist: def __init__(self): self.head=None self.data=None def isEmpty(self): if self.head: return False else: return True def length(self): if self.isEmpty(): return 0 else: t = self.head n = 1 while t.next: if t.next == self.head: break t = t.next n = n + 1 return n def addhead(self,data): node = Node(data) if self.isEmpty(): self.head = node self.tail = self.head else: node.next = self.head self.head = node self.tail.next = self.head def addtail(self,data): node=Node(data) if self.isEmpty(): self.addhead(data) else: t=self.head n=1 l=self.length() while n<l: n=n+1 t=t.next t.next=node node.next=self.head self.tail=node def delete(self,index): if self.isEmpty(): print("The linked list is empty") else: t = self.head l = self.length() if index == 0: self.head = t.next self.tail.next = self.head elif index == l - 1: n = 1 while n < l - 1: t = t.next n = n + 1 t.next = self.head self.tail = t elif index > l - 1: print("Out of range") elif index < 0: print("Wrong operation") else: n = 1 while n < index - 1: t = t.next n = n + 1 a = t.next.next t.next = a def insert(self,data,index): l = self.length() if index == 0 or self.isEmpty(): self.addhead(data) elif index >= l: self.addtail(data) else: node = Node(data) t = self.head n = 1 while n < index - 1: t = t.next n = n + 1 a = t.next t.next = node node.next = a def search(self,a): t=self.head for i in range(a): t=t.next return t.data def form(self,datalist): self.addhead(datalist[0]) for i in range(1,len(datalist)): self.addtail(datalist[i]) t = self.head while t.next != self.head: t = t.nextn,p=map(int,input().split(' '))data=[]p=p-1for i in range(1,n+1): data.append(i)print(data)datalist=[]for i in range(len(data)): datalist.append(int(data[i]))link=linklist()link.form(datalist)a=pb=[]while link.length()>0: b.append(link.search(a)) link.delete(a) a=a+p while a>=link.length(): a=a-link.length()print(b)
改错如下:
```python
class Node:
def __init__(self, data):
self.data = data
self.next = None
class LinkList:
def __init__(self):
self.head = None
self.tail = None
def isEmpty(self):
if self.head:
return False
else:
return True
def length(self):
if self.isEmpty():
return 0
else:
t = self.head
n = 1
while t.next:
if t.next == self.head:
break
t = t.next
n += 1
return n
def addhead(self, data):
node = Node(data)
if self.isEmpty():
self.head = node
self.tail = self.head
else:
node.next = self.head
self.head = node
self.tail.next = self.head
def addtail(self, data):
node = Node(data)
if self.isEmpty():
self.addhead(data)
else:
t = self.head
n = 1
l = self.length()
while n < l:
n += 1
t = t.next
t.next = node
node.next = self.head
self.tail = node
def delete(self, index):
if self.isEmpty():
print("The linked list is empty")
else:
t = self.head
l = self.length()
if index == 0:
self.head = t.next
self.tail.next = self.head
elif index == l - 1:
n = 1
while n < l - 1:
t = t.next
n += 1
t.next = self.head
self.tail = t
elif index > l - 1:
print("Out of range")
elif index < 0:
print("Wrong operation")
else:
n = 1
while n < index:
t = t.next
n += 1
a = t.next.next
t.next = a
def insert(self, data, index):
l = self.length()
if index == 0 or self.isEmpty():
self.addhead(data)
elif index >= l:
self.addtail(data)
else:
node = Node(data)
t = self.head
n = 1
while n < index:
t = t.next
n += 1
a = t.next
t.next = node
node.next = a
def search(self, a):
t = self.head
for i in range(a):
t = t.next
return t.data
def form(self, datalist):
self.addhead(datalist[0])
for i in range(1, len(datalist)):
self.addtail(datalist[i])
t = self.head
while t.next != self.head:
t = t.next
n, p = map(int, input().split(' '))
data = [i for i in range(1, n+1)]
print(data)
datalist = []
for i in range(len(data)):
datalist.append(data[i])
link = LinkList()
link.form(datalist)
a = p-1
b = []
while link.length() > 0:
b.append(link.search(a))
link.delete(a)
a += p-1
while a >= link.length():
a -= link.length()
print(b)
```
n=input() m=int(input()) for i in range(0,m): a,b,c,d=map(str,input().split()) p=int(a) q=int(b) s=n[p:q:1] n=n.replace(s,"") t=n.find(d) z=n[0:t:1] x=n[t:len(n):1] w=z+s+x print(w)修改错误
好的,我看出来了,你需要在代码前面加上一个空格或者四个空格才能表示为代码格式。这里是修改后的代码:
```python
n = input()
m = int(input())
for i in range(0, m):
a, b, c, d = map(str, input().split())
p = int(a)
q = int(b)
s = n[p:q+1]
n = n.replace(s, "")
t = n.find(d)
z = n[0:t]
x = n[t:len(n)]
w = z + s + x
print(w)
```
注意到,在第 8 行中,我们将 `q` 加了一,这是因为在 Python 中,字符串切片的区间是左闭右开的,即 `[p, q)`,所以需要将 `q` 加一才能得到正确的子串。
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