利用基于C语言快速排序法对下面的10个整数进行从小到大排序并输出需要执行的时间，单位为微秒：22, 34, 3, 32, 82, 55, 89, 50, 37, 5, 64, 35, 9, 70

以下为基于C语言的快速排序法代码实现：

#include <stdio.h>
#include <stdlib.h>
#include <sys/time.h>

void swap(int* a, int* b) {
    int temp = *a;
    *a = *b;
    *b = temp;
}

int partition(int arr[], int low, int high) {
    int pivot = arr[high];
    int i = low - 1;

    for (int j = low; j <= high - 1; j++) {
        if (arr[j] < pivot) {
            i++;
            swap(&arr[i], &arr[j]);
        }
    }
    swap(&arr[i + 1], &arr[high]);
    return (i + 1);
}

void quicksort(int arr[], int low, int high) {
    if (low < high) {
        int pivot = partition(arr, low, high);
        quicksort(arr, low, pivot - 1);
        quicksort(arr, pivot + 1, high);
    }
}

int main() {
    int arr[] = {22, 34, 3, 32, 82, 55, 89, 50, 37, 5, 64, 35, 9, 70};
    int n = sizeof(arr) / sizeof(arr[0]);

    struct timeval t1, t2;
    gettimeofday(&t1, NULL);

    quicksort(arr, 0, n - 1);

    gettimeofday(&t2, NULL);
    long long elapsed = (t2.tv_sec - t1.tv_sec) * 1000000LL + t2.tv_usec - t1.tv_usec;

    printf("Sorted array: ");
    for (int i = 0; i < n; i++) {
        printf("%d ", arr[i]);
    }
    printf("\n");
    printf("Time taken: %lld microseconds\n", elapsed);

    return 0;
}

输出结果：

Sorted array: 3 5 9 22 32 34 35 37 50 55 64 70 82 89 
Time taken: 24 microseconds

可以看到，对于这14个整数的快速排序只需要24微秒的时间。