1+rand(size(xo)).*(u-1)
时间: 2023-10-10 19:08:14 浏览: 37
This code generates a random matrix of the same size as xo, where each element is multiplied by (u-1). The rand() function generates random numbers between 0 and 1, so multiplying by (u-1) scales these numbers to be between 0 and (u-1). The .* operator performs element-wise multiplication between the random matrix and (u-1).
相关问题
X(n,:)=1+rand(size(xo)).*(u-1)
This is a MATLAB code that creates a matrix X with the same number of rows as the input matrix xo, and random values between 0 and u-1 for each element in X.
Here's a breakdown of the code:
- X(n,:) = 1: This initializes each row of the matrix X to 1.
- rand(size(xo)): This creates a matrix of random values with the same size as xo.
- .*(u-1): This multiplies each element in the random matrix by u-1, which scales the values to be between 0 and u-1.
Overall, the code generates a new matrix X with the same size as xo, but with random values between 0 and u-1.
MATLAB 中求解sqrt(x.^2 - x.y + y.^2).... (1+(-0.2+noise).*(6.sqrt(3).(x.^3+y.^3-6.*x.^2.*y-6.*x.y.^2))/(2.((x.^2+y.^2-x.*y)/3)^(3/2)))-5,并将解绘制成二维曲线
你可以使用MATLAB中的`fimplicit`函数来绘制该方程在二维平面上的曲线。具体实现如下:
```matlab
% 定义函数句柄
fun = @(x, y) sqrt(x.^2 - x.*y + y.^2) .* (1+(-0.2).*(6.*sqrt(3).*(x.^3+y.^3-6.*x.^2.*y-6.*x.*y.^2))/(2.*((x.^2+y.^2-x.*y)/3)^(3/2)))-5;
% 设置容差
tolerance = 0.1;
% 绘制二维曲线
fimplicit(@(x,y) fun(x+tolerance*(rand()-0.5), y+tolerance*(rand()-0.5)), [-10, 10, -10, 10]);
xlabel('x');
ylabel('y');
```
在上述代码中,我们首先定义了一个函数句柄`fun`,用于表示要求解的方程。然后,我们使用`fimplicit`函数绘制了方程在二维平面上的曲线。由于`fimplicit`函数只能接受一个二元函数作为参数,因此我们在绘制曲线时,将函数句柄包装在了一个匿名函数中,并在匿名函数中加入了一定的误差。
最后,我们使用`xlabel`和`ylabel`函数分别设置了x轴和y轴的标签。