Write a C program that inputs three strings that represent integers, converts the strings to integers sums the values, and prints the total of their values.
时间: 2024-03-13 20:47:01 浏览: 22
好的,以下是一个符合您要求的 C 语言程序:
```c
#include <stdio.h>
#include <stdlib.h> // 包含 atoi 函数
int main() {
// 定义需要输入的三个字符串
char str1[100], str2[100], str3[100];
// 输入三个字符串
printf("Please enter the first number: ");
scanf("%s", str1);
printf("Please enter the second number: ");
scanf("%s", str2);
printf("Please enter the third number: ");
scanf("%s", str3);
// 将三个字符串转为整数并求和
int num1 = atoi(str1);
int num2 = atoi(str2);
int num3 = atoi(str3);
int sum = num1 + num2 + num3;
// 输出结果
printf("The sum of the three numbers is: %d\n", sum);
return 0;
}
```
程序首先提示用户输入三个字符串,然后使用 `scanf` 函数读取用户的输入。接着,使用 `atoi` 函数将三个字符串转换为整数,并求它们的和。最后,输出结果。
相关问题
Write a program that inputs four strings that represent integers, converts the strings to integers sums the values, and prints the total of the four values.
Sure, here is a Python program that does what you described:
```python
num1 = input("Enter the first integer: ")
num2 = input("Enter the second integer: ")
num3 = input("Enter the third integer: ")
num4 = input("Enter the fourth integer: ")
# convert strings to integers and sum them up
total = int(num1) + int(num2) + int(num3) + int(num4)
# print the total
print("The total of the four integers is:", total)
```
You can copy and paste this code into a Python IDE or text editor, save it with a .py extension, and run it to see the results. When you run the program, it will prompt you to enter four integers as strings, and then it will convert them to integers, sum them up, and print the total.
Write a C program that inputs a series of integers and passes them one at a time to function even which uses the modulus operator to determine whether an integer is even.The function should take an integer argument and re
Sure, here's an example C program that takes a series of integers as input and passes them to a function called `even` that checks whether each integer is even or odd:
```c
#include <stdio.h>
int even(int num) {
if (num % 2 == 0) {
return 1;
}
else {
return 0;
}
}
int main() {
int num, result;
printf("Enter a series of integers (enter -1 to end):\n");
do {
scanf("%d", &num);
if (num != -1) {
result = even(num);
if (result == 1) {
printf("%d is even\n", num);
}
else {
printf("%d is odd\n", num);
}
}
} while (num != -1);
return 0;
}
```
In this program, we use a `do-while` loop to repeatedly prompt the user for input until they enter `-1`. Each integer entered by the user is passed to the `even` function, which uses the modulus operator (`%`) to determine whether the integer is even or odd. If the result is 0, the integer is odd; if the result is 1, the integer is even. The function returns either 1 or 0 depending on whether the integer is even or odd.
In the `main` function, we call `even` for each integer entered by the user and print a message indicating whether the integer is even or odd.