将这个代码换成c语言panduan='true' sum=[0,0,0] m=input().split() text=[] for i in range(5): text.append(input().split()) n=input().split() sum[0]=int(m[0]) sum[1]=int(m[1]) sum[2]=int(m[2]) for j in range(5): text[j].append(int(text[j][1])-int(text[j][4])) text[j].append(int(text[j][2])-int(text[j][5])) text[j].append(int(text[j][3])-int(text[j][6])) if int(n[1])>int(m[0]) or int(n[2])>int(m[1]) or int(n[3])>int(m[2]): panduan='false' for i in range(5): sum[0]+=int(text[i][4]) sum[1]+=int(text[i][5]) sum[2]+=int(text[i][6]) if str(n[0])==str(text[i][0]): if int(n[1])<=text[i][7] and int(n[2])<=text[i][8] and int(n[3])<=text[i][9]: text[i][4]=int(text[i][4])+int(n[1]) text[i][5]=int(text[i][5])+int(n[2]) text[i][6]=int(text[i][6])+int(n[3]) text[i][7]=int(text[i][7])-int(n[1]) text[i][8]=int(text[i][8])-int(n[2]) text[i][9]=int(text[i][9])-int(n[3]) m[0]=int(m[0])-int(n[1]) m[1]=int(m[1])-int(n[2]) m[2]=int(m[2])-int(n[3]) else: panduan='false' for j in range(5): for i in range(5): if text[i][7]==0 and text[i][8]==0 and text[i][9]==0: continue elif int(m[0])>=text[i][7] and int(m[1])>=text[i][8] and int(m[2])>=text[i][9]: m[0]=int(m[0])+int(text[i][4]) m[1]=int(m[1])+int(text[i][5]) m[2]=int(m[2])+int(text[i][6]) text[i][7]=0 text[i][8]=0 text[i][9]=0 if m[0]!=sum[0] or m[1]!=sum[1] or m[2]!=sum[2]: panduan='false' print(panduan)

把这段 Python 代码转换成 C 语言的代码如下：

#include <stdio.h>
#include <stdbool.h>
#include <stdlib.h>
#include <string.h>

#define MAX_LEN 10

int main() {
char panduan[] = "true";
int sum[3] = {0, 0, 0};
char m[MAX_LEN];
char text[5][10];
char n[4];

fgets(m, MAX_LEN, stdin);
char *token = strtok(m, " ");
sum[0] = atoi(token);
token = strtok(NULL, " ");
sum[1] = atoi(token);
token = strtok(NULL, " ");
sum[2] = atoi(token);

for (int i = 0; i < 5; i++) {
fgets(text[i], MAX_LEN, stdin);
token = strtok(text[i], " ");
for (int j = 1; j < 7; j++) {
token = strtok(NULL, " ");
}
text[i][7] = atoi(strtok(NULL, " ")) - atoi(strtok(NULL, " "));
text[i][8] = atoi(strtok(NULL, " ")) - atoi(strtok(NULL, " "));
text[i][9] = atoi(strtok(NULL, " ")) - atoi(strtok(NULL, " "));
}

fgets(n, 4, stdin);
token = strtok(n, " ");
char name[MAX_LEN];
strcpy(name, token);

if (atoi(strtok(NULL, " ")) > sum[0] || atoi(strtok(NULL, " ")) > sum[1] || atoi(strtok(NULL, " ")) > sum[2]) {
strcpy(panduan, "false");
}

for (int i = 0; i < 5; i++) {
sum[0] += atoi(strtok(text[i], " "));
sum[1] += atoi(strtok(NULL, " "));
sum[2] += atoi(strtok(NULL, " "));
if (strcmp(name, strtok(NULL, " ")) == 0) {
int a = atoi(strtok(NULL, " "));
int b = atoi(strtok(NULL, " "));
int c = atoi(strtok(NULL, " "));
if (a <= atoi(&text[i][7]) && b <= atoi(&text[i][8]) && c <= atoi(&text[i][9])) {
sprintf(&text[i][4], "%d", atoi(&text[i][4]) + a);
sprintf(&text[i][5], "%d", atoi(&text[i][5]) + b);
sprintf(&text[i][6], "%d", atoi(&text[i][6]) + c);
sprintf(&text[i][7], "%d", atoi(&text[i][7]) - a);
sprintf(&text[i][8], "%d", atoi(&text[i][8]) - b);
sprintf(&text[i][9], "%d", atoi(&text[i][9]) - c);
sum[0] -= a;
sum[1] -= b;
sum[2] -= c;
} else {
strcpy(panduan, "false");
}
}
}

for (int j = 0; j < 5; j++) {
for (int i = 0; i < 5; i++) {
if (text[i][7] == '0' && text[i][8] == '0' && text[i][9] == '0') {
continue;
} else if (atoi(&m[0]) >= atoi(&text[i][7]) && atoi(&m[2]) >= atoi(&text[i][8]) && atoi(&m[2]) >= atoi(&text[i][9])) {
sum[0] += atoi(&text[i][4]);
sum[1] += atoi(&text[i][5]);
sum[2] += atoi(&text[i][6]);
sprintf(&m[0], "%d", atoi(&m[0]) + atoi(&text[i][7]));
sprintf(&m[1], "%d", atoi(&m[1]) + atoi(&text[i][8]));
sprintf(&m[2], "%d", atoi(&m[2]) + atoi(&text[i][9]));
sprintf(&text[i][7], "%d", 0);
sprintf(&text[i][8], "%d", 0);
sprintf(&text[i][9], "%d", 0);
}
}
}

if (sum[0] != atoi(&m[0]) || sum[1] != atoi(&m[1]) || sum[2] != atoi(&m[2])) {
strcpy(panduan, "false");
}

printf("%s", panduan);
return 0;
}

注意，这里使用了 C 语言的字符串处理函数 strtok 和 sprintf，需要在头文件中包含 stdlib.h 和 string.h。同时，Python 中的列表在 C 中用二维数组来表示。另外，Python 中的字符串与数字可以互相转换，但是在 C 中需要使用 atoi 和 sprintf 等函数来实现。