liang-barsky算法Python
时间: 2023-07-10 14:41:12 浏览: 118
python算法
以下是 Liang-Barsky 算法的 Python 实现:
```python
def liang_barsky(x1, y1, x2, y2, xmin, ymin, xmax, ymax):
dx = x2 - x1
dy = y2 - y1
p1 = -dx
p2 = dx
p3 = -dy
p4 = dy
q1 = x1 - xmin
q2 = xmax - x1
q3 = y1 - ymin
q4 = ymax - y1
posarr = [1]
negarr = [0]
posind = 1
negind = 1
if p1 == 0 and q1 < 0 or p3 == 0 and q3 < 0:
print("Line is outside the clipping window")
return
if p1 != 0:
r1 = q1 / p1
r2 = q2 / p2
if p1 < 0:
negarr.append(r1)
posarr.append(r2)
negind += 1
posind += 1
else:
negarr.append(r2)
posarr.append(r1)
negind += 1
posind += 1
if p3 != 0:
r3 = q3 / p3
r4 = q4 / p4
if p3 < 0:
negarr.append(r3)
posarr.append(r4)
negind += 1
posind += 1
else:
negarr.append(r4)
posarr.append(r3)
negind += 1
posind += 1
xn1 = 0
yn1 = 0
xn2 = 0
yn2 = 0
rn1 = 0
rn2 = 1
for i in range(1, posind):
rn = posarr[i]
if rn < rn2:
rn2 = rn
for i in range(1, negind):
rn = negarr[i]
if rn > rn1:
rn1 = rn
xn1 = x1 + rn1 * dx
yn1 = y1 + rn1 * dy
xn2 = x1 + rn2 * dx
yn2 = y1 + rn2 * dy
print("The coordinates of the clipped line are: ({:.2f}, {:.2f}) and ({:.2f}, {:.2f})".format(xn1, yn1, xn2, yn2))
```
这个程序假设输入的线段的起点和终点坐标分别为 (x1, y1) 和 (x2, y2),裁剪窗口的四个边界坐标分别为 xmin, ymin, xmax 和 ymax。函数 `liang_barsky` 的输出为经过裁剪后的线段的两个端点的坐标。
阅读全文