用C语言以及easxy实现贪吃蛇游戏中每次得到的游戏积分的排行榜
时间: 2024-05-14 19:19:20 浏览: 11
实现贪吃蛇游戏积分排行榜,需要以下步骤:
1. 定义一个结构体,表示每个玩家的信息,包括玩家姓名和得分。例如:
```
typedef struct {
char name[20];
int score;
} Player;
```
2. 定义一个数组,用来存储所有玩家的信息。例如:
```
Player players[10];
```
3. 在游戏结束时,将当前玩家的信息添加到数组中。可以遍历整个数组,找到第一个空位,然后将当前玩家信息赋值给该空位。例如:
```
int i;
for (i = 0; i < 10; i++) {
if (players[i].score == 0) {
strcpy(players[i].name, name);
players[i].score = score;
break;
}
}
```
4. 对数组进行排序,按照得分从高到低排列。可以使用冒泡排序或快速排序等算法。例如:
```
int i, j;
for (i = 0; i < 9; i++) {
for (j = i + 1; j < 10; j++) {
if (players[i].score < players[j].score) {
Player temp = players[i];
players[i] = players[j];
players[j] = temp;
}
}
}
```
5. 将排好序的数组输出到屏幕上,显示排行榜。例如:
```
printf("Rank\tName\tScore\n");
for (i = 0; i < 10; i++) {
printf("%d\t%s\t%d\n", i+1, players[i].name, players[i].score);
}
```
完整代码示例:
```
#include <stdio.h>
#include <string.h>
typedef struct {
char name[20];
int score;
} Player;
int main()
{
Player players[10] = {0};
int i, score;
char name[20];
for (i = 0; i < 3; i++) {
printf("Player %d: ", i+1);
scanf("%s%d", name, &score);
int j;
for (j = 0; j < 10; j++) {
if (players[j].score == 0) {
strcpy(players[j].name, name);
players[j].score = score;
break;
}
}
for (j = 0; j < 9; j++) {
int k;
for (k = j + 1; k < 10; k++) {
if (players[j].score < players[k].score) {
Player temp = players[j];
players[j] = players[k];
players[k] = temp;
}
}
}
printf("Rank\tName\tScore\n");
for (j = 0; j < 10; j++) {
if (players[j].score == 0) {
break;
}
printf("%d\t%s\t%d\n", j+1, players[j].name, players[j].score);
}
}
return 0;
}
```