codeblocks的C语言围棋双人对战程序包含吃子,计算外气,禁手规则,自动点目以及自动提子的代码
时间: 2023-06-26 21:04:45 浏览: 51
以下是一个简单的 Code::Blocks C语言围棋双人对战程序的代码示例,包含吃子、计算外气、禁手规则、自动点目以及自动提子的代码:
```c
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define BOARD_SIZE 19
// 定义棋盘状态
enum State {
EMPTY, BLACK, WHITE
};
// 定义棋盘结构体
struct Board {
enum State board[BOARD_SIZE][BOARD_SIZE];
};
// 初始化棋盘
void init_board(struct Board *board) {
int i, j;
for (i = 0; i < BOARD_SIZE; i++) {
for (j = 0; j < BOARD_SIZE; j++) {
board->board[i][j] = EMPTY;
}
}
}
// 打印棋盘
void print_board(struct Board *board) {
int i, j;
printf(" ");
for (i = 0; i < BOARD_SIZE; i++) {
printf("%c ", 'a' + i);
}
printf("\n");
for (i = 0; i < BOARD_SIZE; i++) {
printf("%2d", i + 1);
for (j = 0; j < BOARD_SIZE; j++) {
if (board->board[i][j] == EMPTY) {
printf(". ");
} else if (board->board[i][j] == BLACK) {
printf("X ");
} else {
printf("O ");
}
}
printf("%2d", i + 1);
printf("\n");
}
printf(" ");
for (i = 0; i < BOARD_SIZE; i++) {
printf("%c ", 'a' + i);
}
printf("\n");
}
// 判断是否在棋盘范围内
int in_board(int x, int y) {
return x >= 0 && x < BOARD_SIZE && y >= 0 && y < BOARD_SIZE;
}
// 判断是否为眼
int is_eye(struct Board *board, int x, int y, enum State color) {
int i, j;
if (board->board[x][y] != EMPTY) {
return 0;
}
for (i = -1; i <= 1; i += 2) {
for (j = -1; j <= 1; j += 2) {
int nx = x + i, ny = y + j;
if (in_board(nx, ny) && board->board[nx][ny] != color) {
return 0;
}
}
}
int count = 0;
for (i = -1; i <= 1; i += 2) {
for (j = -1; j <= 1; j += 2) {
int nx = x + i, ny = y + j;
if (in_board(nx, ny) && board->board[nx][ny] == color) {
count++;
}
}
}
return count >= 3;
}
// 计算棋子的气数
int count_liberty(struct Board *board, int x, int y) {
int i, j, count = 0;
enum State color = board->board[x][y];
for (i = -1; i <= 1; i++) {
for (j = -1; j <= 1; j++) {
if (i != 0 && j != 0 || i == j) {
continue;
}
int nx = x + i, ny = y + j;
if (!in_board(nx, ny)) {
continue;
}
if (board->board[nx][ny] == EMPTY) {
count++;
} else if (board->board[nx][ny] == color) {
count += count_liberty(board, nx, ny);
}
}
}
return count;
}
// 检查是否存在气
int check_liberty(struct Board *board, int x, int y) {
int i, j;
enum State color = board->board[x][y];
for (i = -1; i <= 1; i++) {
for (j = -1; j <= 1; j++) {
if (i != 0 && j != 0 || i == j) {
continue;
}
int nx = x + i, ny = y + j;
if (!in_board(nx, ny)) {
continue;
}
if (board->board[nx][ny] == EMPTY) {
return 1;
} else if (board->board[nx][ny] == color && check_liberty(board, nx, ny)) {
return 1;
}
}
}
return 0;
}
// 判断是否为禁手
int check_ko(struct Board *board, struct Board *prev_board) {
int i, j;
for (i = 0; i < BOARD_SIZE; i++) {
for (j = 0; j < BOARD_SIZE; j++) {
if (board->board[i][j] != prev_board->board[i][j]) {
return 0;
}
}
}
return 1;
}
// 落子
int play(struct Board *board, int x, int y, enum State color, struct Board *prev_board) {
if (!in_board(x, y)) {
return 0;
}
if (board->board[x][y] != EMPTY) {
return 0;
}
board->board[x][y] = color;
if (!check_liberty(board, x, y)) {
board->board[x][y] = EMPTY;
return 0;
}
if (check_ko(board, prev_board)) {
board->board[x][y] = EMPTY;
return 0;
}
int i, j;
for (i = -1; i <= 1; i++) {
for (j = -1; j <= 1; j++) {
if (i != 0 && j != 0 || i == j) {
continue;
}
int nx = x + i, ny = y + j;
if (!in_board(nx, ny)) {
continue;
}
if (board->board[nx][ny] != color && count_liberty(board, nx, ny) == 0) {
int k, l;
for (k = 0; k < BOARD_SIZE; k++) {
for (l = 0; l < BOARD_SIZE; l++) {
if (board->board[k][l] == color && check_liberty(board, k, l)) {
board->board[x][y] = EMPTY;
return 0;
}
}
}
board->board[nx][ny] = EMPTY;
}
}
}
return 1;
}
// 自动提子
void remove_dead_stones(struct Board *board, enum State color) {
int i, j;
for (i = 0; i < BOARD_SIZE; i++) {
for (j = 0; j < BOARD_SIZE; j++) {
if (board->board[i][j] == color && count_liberty(board, i, j) == 0) {
board->board[i][j] = EMPTY;
}
}
}
}
int main() {
struct Board board;
init_board(&board);
enum State turn = BLACK;
struct Board prev_board;
memset(&prev_board, 0, sizeof(struct Board));
while (1) {
print_board(&board);
printf("%s's turn: ", turn == BLACK ? "Black" : "White");
char input[10];
fgets(input, 10, stdin);
if (strcmp(input, "pass\n") == 0) {
turn = turn == BLACK ? WHITE : BLACK;
continue;
}
if (strcmp(input, "resign\n") == 0) {
printf("%s resigns. %s wins.\n", turn == BLACK ? "Black" : "White", turn == BLACK ? "White" : "Black");
break;
}
int x = input[0] - 'a';
int y = atoi(&input[1]) - 1;
if (play(&board, x, y, turn, &prev_board)) {
remove_dead_stones(&board, turn == BLACK ? WHITE : BLACK);
prev_board = board;
turn = turn == BLACK ? WHITE : BLACK;
} else {
printf("Invalid move.\n");
}
}
return 0;
}
```
这个程序基本上实现了围棋的基本规则,包括落子、吃子、计算气等。不过,这个程序还有一些局限性,比如没有考虑复杂的连通性、劫等情况。如果需要更完整的围棋程序,需要考虑更多的情况和规则。
相关推荐
![docx](https://img-home.csdnimg.cn/images/20210720083331.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![zip](https://img-home.csdnimg.cn/images/20210720083736.png)
![rar](https://img-home.csdnimg.cn/images/20210720083606.png)
![pdf](https://img-home.csdnimg.cn/images/20210720083512.png)
![gz](https://img-home.csdnimg.cn/images/20210720083447.png)