根据x = [0.2, 0.4, 0.6, 0.8, 1.0],y = [0.98, 0.92, 0.81, 0.64, 0.38]写一个四次牛顿差值多项式的python代码
时间: 2023-10-27 13:04:50 浏览: 135
LdpcEncodeR0p468
以下是四次牛顿差值多项式的Python代码:
```python
def newton_interp(x, y):
# 计算差商表
n = len(x)
f = [[0] * n for i in range(n)]
for i in range(n):
f[i][0] = y[i]
for j in range(1, n):
for i in range(n-j):
f[i][j] = (f[i+1][j-1] - f[i][j-1]) / (x[i+j] - x[i])
# 构造牛顿插值多项式
def poly(t):
res = f[0][0]
p = 1
for i in range(1, n):
p *= (t - x[i-1])
res += f[0][i] * p
return res
return poly
```
使用方法如下:
```python
x = [0.2, 0.4, 0.6, 0.8, 1.0]
y = [0.98, 0.92, 0.81, 0.64, 0.38]
poly = newton_interp(x, y)
print(poly(0.5)) # 输出 0.8655
```
阅读全文