c语言设有函数y=f(x),任给一个实数x，求y的值。其中： f(x)=g(x)-7 g(x)=h(x)+8 h(x)=x3-2x

根据题意，f(x) = g(x) - 7 = h(x) + 1，而 g(x) = h(x) + 8，所以可得 f(x) = h(x) + 1 = g(x) - 7 = h(x) + 1 - 7 = h(x) - 6
所以 f(x) = g(x) - 7 = h(x) + 8 - 7 = h(x) + 1
所以 f(x) = h(x) - 6 = x^3 - 2x - 6
将给定的实数x代入f(x)中，可得y的值，即 y = f(x) = x^3 - 2x - 6

相关问题

用c语言编程设有函数y=f(x),任给一个实数x，求y的值。其中：f(x)=g(x)-7，g(x)=h(x)+8， h(x)=x3-2x

回答：可以使用以下C语言代码来计算y的值：

#include <stdio.h>
#include <math.h>

float h(float x) {
    return pow(x, 3) - 2 * x;
}

float g(float x) {
    return h(x) + 8;
}

float f(float x) {
    return g(x) - 7;
}

int main() {
    float x = 3.14; // 可以替换为任意实数
    float y = f(x);
    printf("y = %f\n", y);
    return 0;
}

输出结果会显示y的值。

用c语言编程设有函数y=f(x),任给一个实数x，求y的值。其中：f(x)=g(x)-7, g(x)=h(x)+8,h(x)=x3-2x

Sure, I can answer that question. Given a real number x, the value of y for the function y=f(x)=g(x)-7, where g(x)=h(x)+8 and h(x)=x^3-2x is calculated by first finding the value of h(x), which is obtained by substituting the value of x in the expression h(x)=x^3-2x. Once we have the value of h(x), it can be used to find the value of g(x) by adding 8 to it, giving us g(x)=h(x)+8. And finally, the value of y=f(x) is calculated by subtracting 7 from the value of g(x), i.e. y=g(x)-7.