用python编写4*4数字华容道游戏
时间: 2024-05-01 18:18:09 浏览: 15
可以通过以下步骤来编写4*4数字华容道游戏:
1. 创建一个4*4的方格,用数字(1-15)填充其中15个小方格,留一个空白方格,用0表示。
2. 随机选择两个位置(i,j)和(k,l)并交换其对应的数字,重复多次以打乱方格的顺序。
3. 使用Pygame创建游戏界面,并将方格显示在窗口中。
4. 处理玩家的键盘事件,例如按上、下、左、右箭头键时,移动数字方格来重新排列数字。
5. 检查数字方格的顺序是否与目标状态匹配,即数字按顺序排列,最后一个方格为空。如果是,则游戏胜利。
以下是一个基本的代码框架:
```
import pygame
import random
# initialize pygame
pygame.init()
# set colors
WHITE = (255, 255, 255)
BLACK = (0, 0, 0)
# set window size
WINDOW_SIZE = (400, 400)
# set block size
BLOCK_SIZE = 100
# create font object
font = pygame.font.Font(None, 36)
# create grid
grid = [[1, 2, 3, 4],
[5, 6, 7, 8],
[9, 10, 11, 12],
[13, 14, 15, 0]]
# shuffle grid
for i in range(100):
row1 = random.randint(0, 3)
col1 = random.randint(0, 3)
row2 = random.randint(0, 3)
col2 = random.randint(0, 3)
grid[row1][col1], grid[row2][col2] = grid[row2][col2], grid[row1][col1]
# create window object
screen = pygame.display.set_mode(WINDOW_SIZE)
# set window title
pygame.display.set_caption("4x4 Number Puzzle Game")
# set clock object
clock = pygame.time.Clock()
# main game loop
while True:
# handle events
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
quit()
# draw grid
for row in range(4):
for col in range(4):
rect = pygame.Rect(col * BLOCK_SIZE, row * BLOCK_SIZE, BLOCK_SIZE, BLOCK_SIZE)
pygame.draw.rect(screen, WHITE, rect)
text = font.render(str(grid[row][col]), True, BLACK)
text_rect = text.get_rect(center=rect.center)
screen.blit(text, text_rect)
# update screen
pygame.display.update()
# set game FPS
clock.tick(60)
```