写一个verilog流水灯代码
时间: 2023-05-19 13:06:20 浏览: 130
module flow_light(
input clk,
output reg [7:0] led
);
reg [2:0] cnt;
always @(posedge clk) begin
case(cnt)
3'd0: led <= 8'b00000001;
3'd1: led <= 8'b00000010;
3'd2: led <= 8'b00000100;
3'd3: led <= 8'b00001000;
3'd4: led <= 8'b00010000;
3'd5: led <= 8'b00100000;
3'd6: led <= 8'b01000000;
3'd7: led <= 8'b10000000;
endcase
cnt <= cnt + 1;
end
endmodule
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写一段verilog流水灯代码
module led_sequence(
input clk, // 时钟信号
output reg [7:0] led // LED输出信号
);
reg [3:0] counter; // 计数器
always @(posedge clk) begin
// 计数器加1
counter <= counter + 1;
// 根据计数器的值控制LED输出
case(counter)
4'd0: led <= 8'b00000001;
4'd1: led <= 8'b00000010;
4'd2: led <= 8'b00000100;
4'd3: led <= 8'b00001000;
4'd4: led <= 8'b00010000;
4'd5: led <= 8'b00100000;
4'd6: led <= 8'b01000000;
4'd7: led <= 8'b10000000;
endcase
end
endmodule
用VERILOG写的一个流水灯代码
以下是一个基本的Verilog代码,实现一个4位流水灯:
```verilog
module led_shift(
input clk,
input rst,
output reg [3:0] led
);
reg [25:0] count; // 计数器
always @(posedge clk or posedge rst)
begin
if (rst == 1'b1) begin
count <= 0;
led <= 4'b0001;
end
else begin
count <= count + 1;
if (count == 26'd500000) begin // 延时
count <= 0;
led <= {led[2:0], led[3]};
end
end
end
endmodule
```
这个代码通过一个时钟信号 `clk` 和一个复位信号 `rst` 控制4个LED灯的输出。具体实现是通过一个计数器 `count` 来控制延时,并且让灯的输出循环向左移动。当复位信号为高电平时,计数器和灯的输出都被重置。