C语言写一个带人机的五子棋游戏

好的，以下是一个简单的带人机的五子棋游戏的C语言代码：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define SIZE 15

int board[SIZE][SIZE];

void init_board() {
    int i, j;
    for (i = 0; i < SIZE; i++) {
        for (j = 0; j < SIZE; j++) {
            board[i][j] = 0;
        }
    }
}

void print_board() {
    int i, j;
    printf(" ");
    for (i = 0; i < SIZE; i++) {
        printf("%2d ", i + 1);
    }
    printf("\n");
    for (i = 0; i < SIZE; i++) {
        printf("%2d ", i + 1);
        for (j = 0; j < SIZE; j++) {
            if (board[i][j] == 0) {
                printf(".  ");
            } else if (board[i][j] == 1) {
                printf("O  ");
            } else if (board[i][j] == 2) {
                printf("X  ");
            }
        }
        printf("\n");
    }
}

int check_win(int player) {
    int i, j, k;
    for (i = 0; i < SIZE; i++) {
        for (j = 0; j < SIZE; j++) {
            if (board[i][j] == player) {
                for (k = 1; k < 5; k++) {
                    if (i + k < SIZE && board[i + k][j] == player &&
                        i + k - 4 >= 0 && board[i + k - 1][j] == player &&
                        board[i + k - 2][j] == player && board[i + k - 3][j] == player) {
                        return 1;
                    }
                    if (j + k < SIZE && board[i][j + k] == player &&
                        j + k - 4 >= 0 && board[i][j + k - 1] == player &&
                        board[i][j + k - 2] == player && board[i][j + k - 3] == player) {
                        return 1;
                    }
                    if (i + k < SIZE && j + k < SIZE && board[i + k][j + k] == player &&
                        i + k - 4 >= 0 && j + k - 4 >= 0 && board[i + k - 1][j + k - 1] == player &&
                        board[i + k - 2][j + k - 2] == player && board[i + k - 3][j + k - 3] == player) {
                        return 1;
                    }
                    if (i + k < SIZE && j - k >= 0 && board[i + k][j - k] == player &&
                        i + k - 4 >= 0 && j - k + 4 < SIZE && board[i + k - 1][j - k + 1] == player &&
                        board[i + k - 2][j - k + 2] == player && board[i + k - 3][j - k + 3] == player) {
                        return 1;
                    }
                }
            }
        }
    }
    return 0;
}

int player_move(int player) {
    int row, col;
    while (1) {
        printf("Player %d's turn:\n", player);
        printf("Enter row and column: ");
        scanf("%d%d", &row, &col);
        if (row >= 1 && row <= SIZE && col >= 1 && col <= SIZE && board[row - 1][col - 1] == 0) {
            board[row - 1][col - 1] = player;
            return 1;
        } else {
            printf("Invalid move! Please try again.\n");
        }
    }
}

int computer_move(int player) {
    int row, col;
    printf("Computer's turn:\n");
    while (1) {
        row = rand() % SIZE;
        col = rand() % SIZE;
        if (board[row][col] == 0) {
            board[row][col] = player;
            return 1;
        }
    }
}

int main() {
    int player = 1;
    int win = 0;
    init_board();
    srand(time(NULL));
    while (!win) {
        print_board();
        if (player == 1) {
            player_move(player);
        } else {
            computer_move(player);
        }
        win = check_win(player);
        if (win) {
            print_board();
            printf("Player %d wins!\n", player);
        } else {
            player = player == 1 ? 2 : 1;
        }
    }
    return 0;
}

该程序使用了一个二维数组来表示棋盘，其中0表示空位，1表示玩家1的棋子，2表示玩家2（即计算机）的棋子。程序中定义了两个函数，`player_move`和`computer_move`，分别表示玩家和计算机的走棋行为。其中，计算机的走棋行为是随机的。程序通过调用`check_win`函数来判断当前局面是否出现胜者，如果有则游戏结束。程序使用了随机数生成函数`srand`和`rand`，需要包含头文件`stdlib.h`和`time.h`。