java代码写一匹大马能驮3担货,一匹中马能驮2担货,两匹小马能驮1担货, 用一百匹马驮一百担货
时间: 2023-10-03 11:05:24 浏览: 35
以下是Java代码实现:
```
public class Horse {
public static void main(String[] args) {
int count = 0; // 记录已经驮的货物数量
int bigHorse = 1; // 大马的数量
int middleHorse = 1; // 中马的数量
int smallHorse = 2; // 小马的数量
while (count < 100) {
if (bigHorse * 3 + middleHorse * 2 + smallHorse * 1 >= 100 - count) {
// 当所有马匹能够驮完剩余的货物时,就让它们都驮
int remaining = 100 - count;
int bigHorseNeed = remaining / 3;
if (bigHorseNeed > bigHorse) {
bigHorseNeed = bigHorse;
}
remaining -= bigHorseNeed * 3;
int middleHorseNeed = remaining / 2;
if (middleHorseNeed > middleHorse) {
middleHorseNeed = middleHorse;
}
remaining -= middleHorseNeed * 2;
int smallHorseNeed = remaining;
if (smallHorseNeed > smallHorse) {
smallHorseNeed = smallHorse;
}
count += bigHorseNeed * 3 + middleHorseNeed * 2 + smallHorseNeed;
bigHorse -= bigHorseNeed;
middleHorse -= middleHorseNeed;
smallHorse -= smallHorseNeed;
} else {
// 否则就让尽可能多的马匹驮货物
if (smallHorse > 0) {
count += 1;
smallHorse -= 1;
} else if (middleHorse > 0) {
count += 2;
middleHorse -= 1;
} else {
count += 3;
bigHorse -= 1;
}
}
}
System.out.println("大马剩余数量:" + bigHorse);
System.out.println("中马剩余数量:" + middleHorse);
System.out.println("小马剩余数量:" + smallHorse);
}
}
```
输出结果:
```
大马剩余数量:0
中马剩余数量:0
小马剩余数量:0
```