java完整代码100匹马拉100担货，一匹大马能驮3担货，一匹中马能驮2担货，两匹小马能驮1担货，求马各有多少只

以下是一个可能的 Java 代码实现：

public class HorseAndLoad {
    public static void main(String[] args) {
        int totalHorses = 100;
        int totalLoads = 100;
        int bigHorseLoad = 3;
        int middleHorseLoad = 2;
        int smallHorseLoad = 1;

        for (int bigHorse = 0; bigHorse <= totalHorses; bigHorse++) {
            for (int middleHorse = 0; middleHorse <= totalHorses - bigHorse; middleHorse++) {
                int smallHorse = totalHorses - bigHorse - middleHorse;
                int totalLoadByHorses = bigHorse * bigHorseLoad + middleHorse * middleHorseLoad + smallHorse / 2;
                if (totalLoadByHorses == totalLoads) {
                    System.out.printf("Big horses: %d, middle horses: %d, small horses: %d.%n", bigHorse, middleHorse, smallHorse);
                }
            }
        }
    }
}

这个程序使用了两个循环来枚举所有可能的马匹数量组合。对于每个组合，它计算所有马匹能够拉的货物总量，并检查它是否等于100。如果是，它就打印出这个组合。注意，由于两匹小马可以组成一匹中马，因此这里将小马数量除以2。