distance on chessboard

The distance on a chessboard refers to the number of squares between two pieces or locations on the board. It is calculated by counting the number of squares a piece must move horizontally, vertically or diagonally to reach its destination. The maximum distance on a chessboard is 14 squares, which is the distance between the two opposite corners.

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distance on chessboard 代码实现

这里提供一个 Python 代码实现，通过输入两个棋盘上的位置，计算它们之间的最短距离。

def distance_on_chessboard(pos1, pos2):
    """
    计算在棋盘上从 pos1 到 pos2 的最短距离
    pos1 和 pos2 是形如 "a1" 或 "h8" 的字符串
    """
    # 将位置字符串转换为坐标
    x1, y1 = ord(pos1[0]) - 97, int(pos1[1]) - 1
    x2, y2 = ord(pos2[0]) - 97, int(pos2[1]) - 1
    
    # 计算横向和纵向的距离
    dx, dy = abs(x2 - x1), abs(y2 - y1)
    
    # 返回最短距离
    return max(dx, dy)

# 测试代码
print(distance_on_chessboard("a1", "h8"))  # 7
print(distance_on_chessboard("d5", "e6"))  # 1
print(distance_on_chessboard("h1", "a8"))  # 7

distance on chessboard C语言代码实现

以下是一个用C语言实现棋盘上两个点之间距离的示例代码：

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int main()
{
    int x1, y1, x2, y2;
    float distance;

    printf("Enter the coordinates of first point (x1 y1): ");
    scanf("%d %d", &x1, &y1);

    printf("Enter the coordinates of second point (x2 y2): ");
    scanf("%d %d", &x2, &y2);

    distance = sqrt(pow(x2 - x1, 2) + pow(y2 - y1, 2));

    printf("The distance between the points (%d,%d) and (%d,%d) is: %f\n", x1, y1, x2, y2, distance);

    return 0;
}

该程序首先提示用户输入两个点的坐标，然后使用sqrt和pow函数计算两点之间的距离，并将结果打印到屏幕上。