优化这段代码使其能够一次性爬取多条信息import requests from bs4 import BeautifulSoup url = "https://www.chinanews.com/importnews.html" headers = { "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/113.0.0.0 Safari/537.36 Edg/113.0.1774.57" } def get_news_list(url): res = requests.get(url=url, headers=headers) res.encoding ='utf-8' soup = BeautifulSoup(res.text, 'html.parser') news_list = [] for news in soup.select('.content_list'): title = news.select(".dd_bt")[2].text.strip() news_list.append(title) return news_list if __name__ == '__main__': news_list = get_news_list(url) for news in news_list: print(news)
时间: 2024-02-26 13:55:54 浏览: 29
import requests
from bs4 import BeautifulSoup
url = "https://www.chinanews.com/importnews.html"
headers = {
"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/113.0.0.0 Safari/537.36 Edg/113.0.1774.57"
}
def get_news_list(url):
res = requests.get(url=url, headers=headers)
res.encoding ='utf-8'
soup = BeautifulSoup(res.text, 'html.parser')
news_list = []
for news in soup.select('.content_list'):
title = news.select(".dd_bt")[2].text.strip()
news_list.append(title)
return news_list
if __name__ == '__main__':
news_list = get_news_list(url)
print('\n'.join(news_list)) # 一次性输出多条信息
相关问题
优化这段代码import requests from bs4 import BeautifulSoup url = "https://www.gupang.com/202305/64619.html" response = requests.get(url) soup = BeautifulSoup(response.content, "html.parser") title = soup.find("h1", class_="title").text content = soup.find("div", class_="content").text print(title) print(content)
可以使用以下方法进行优化:
1. 添加异常处理,以防止请求失败或解析失败导致程序崩溃:
```python
import requests
from bs4 import BeautifulSoup
url = "https://www.gupang.com/202305/64619.html"
try:
response = requests.get(url)
response.raise_for_status() # 抛出异常,如果请求失败
except requests.exceptions.RequestException as e:
print(e)
sys.exit(1)
soup = BeautifulSoup(response.content, "html.parser")
try:
title = soup.find("h1", class_="title").text
content = soup.find("div", class_="content").text
except AttributeError as e:
print(e)
sys.exit(1)
print(title)
print(content)
```
2. 使用`with`语句来管理资源,以确保在使用完文件或网络连接后自动释放资源:
```python
import requests
from bs4 import BeautifulSoup
url = "https://www.gupang.com/202305/64619.html"
try:
with requests.get(url) as response:
response.raise_for_status()
soup = BeautifulSoup(response.content, "html.parser")
title = soup.find("h1", class_="title").text
content = soup.find("div", class_="content").text
except (requests.exceptions.RequestException, AttributeError) as e:
print(e)
sys.exit(1)
print(title)
print(content)
```
这种方法可以避免手动关闭连接或文件,而且代码更加简洁。
import requests from bs4 import BeautifulSoup url="https://www.360kan.com/rank/index?from=siteslibsubpage" response=requests.get(url) html=response.text soup=BeautifulSoup(html,"lxml") content_all=soup.find_all("em") for content in content_all: contentstring=content.string print(contentstring)这个代码怎么爬不出东西
这个代码可能无法爬取到数据的原因有很多,以下是一些可能的原因:
1. 没有设置 User-Agent:有些网站会防止爬虫访问,需要设置 User-Agent 伪装成浏览器访问。
2. 网站反爬虫策略:一些网站会采取反爬虫策略,如设置验证码、限制 IP 访问频率等。
3. 爬取的内容不存在:有些网站的内容是通过 JavaScript 动态加载的,需要使用 Selenium 等工具模拟浏览器操作才能爬取到动态加载的内容。
你可以尝试以下方法来解决问题:
1. 在 requests.get() 中添加 headers 参数来设置 User-Agent,示例代码如下:
```
headers = {
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/58.0.3029.110 Safari/537.3'}
response = requests.get(url, headers=headers)
```
2. 使用 Chrome 开发者工具查看网站的网络请求情况,看看是否有验证码或其他反爬虫策略。
3. 如果爬取的内容是通过 JavaScript 动态加载的,可以使用 Selenium 等工具模拟浏览器操作,示例代码如下:
```
from selenium import webdriver
url = "https://www.360kan.com/rank/index?from=siteslibsubpage"
# 使用 Chrome 浏览器
browser = webdriver.Chrome()
browser.get(url)
# 获取页面源代码
html = browser.page_source
# 解析页面
soup = BeautifulSoup(html, "lxml")
# 获取需要的内容
content_all = soup.find_all("em")
for content in content_all:
contentstring = content.string
print(contentstring)
# 关闭浏览器
browser.quit()
```