i <= Math.sqrt(Math.abs(toCheck))
时间: 2024-05-25 18:17:42 浏览: 11
As an AI language model, I cannot provide a complete solution without knowing the context and purpose of the code. However, I can explain what this line of code does.
This line is a condition that checks if the value of "i" is less than or equal to the square root of the absolute value of "toCheck".
The Math.abs() function returns the absolute value of a number, which means it returns a positive value regardless of whether the original number was positive or negative.
The Math.sqrt() function returns the square root of a number.
Therefore, this condition is checking if the current value of "i" is less than or equal to the square root of the absolute value of "toCheck".
相关问题
j ava求200内的素数
以下是Java代码实现:
```java
public class PrimeNumbers {
public static void main(String[] args) {
int n = 200;
System.out.println("Prime numbers up to " + n + " are:");
for (int i = 2; i <= n; i++) {
if (isPrime(i)) {
System.out.print(i + " ");
}
}
}
// Check if a number is prime or not
public static boolean isPrime(int num) {
if (num < 2) {
return false;
}
for (int i = 2; i <= Math.sqrt(num); i++) {
if (num % i == 0) {
return false;
}
}
return true;
}
}
```
输出结果:
```
Prime numbers up to 200 are:
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97 101 103 107 109 113 127 131 137 139 149 151 157 163 167 173 179 181 191 193 197 199
```
JAVA输出100以内的所有素数
以下是Java代码,可以输出100以内的所有素数:
```java
public class PrimeNumbers {
public static void main(String[] args) {
int n = 100;
// loop through all numbers from 2 to n
for (int i = 2; i <= n; i++) {
boolean isPrime = true;
// check if i is a prime number
for (int j = 2; j <= Math.sqrt(i); j++) {
if (i % j == 0) {
isPrime = false;
break;
}
}
// if i is a prime number, print it
if (isPrime) {
System.out.print(i + " ");
}
}
}
}
```
运行该程序,将输出以下内容:
```
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97
```
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