需求:自己写一套简单导航逻辑。1.导航路径由一个个节点组成,每个节点自定义可到达哪几个节点,根据这样一个网络写出一套算法实时获取最近节点,然后计算出所有可能到达终点的方案中最近的方案,最后返回出最近方案的数组,要求ID类型为string,用c#写
时间: 2023-12-17 09:05:12 浏览: 26
以下是一种简单的导航逻辑,实现了根据节点网络实时获取最近节点和计算最近方案的功能:
```csharp
using System.Collections.Generic;
public class NavigationNode {
public string ID { get; set; }
public List<string> ReachableNodes { get; set; }
public NavigationNode(string id, List<string> reachableNodes) {
ID = id;
ReachableNodes = reachableNodes;
}
}
public class Navigation {
private List<NavigationNode> nodes;
public Navigation(List<NavigationNode> nodes) {
this.nodes = nodes;
}
public string[] GetClosestPath(string startID, string endID) {
// 实时获取最近节点
Dictionary<string, int> distances = new Dictionary<string, int>();
Dictionary<string, string> previousNodes = new Dictionary<string, string>();
foreach (NavigationNode node in nodes) {
distances[node.ID] = int.MaxValue;
}
distances[startID] = 0;
Queue<string> queue = new Queue<string>();
queue.Enqueue(startID);
while (queue.Count > 0) {
string currentID = queue.Dequeue();
foreach (string neighborID in nodes.Find(n => n.ID == currentID).ReachableNodes) {
int distance = distances[currentID] + 1;
if (distance < distances[neighborID]) {
distances[neighborID] = distance;
previousNodes[neighborID] = currentID;
queue.Enqueue(neighborID);
}
}
}
// 计算所有可能到达终点的方案中最近的方案
List<string> path = new List<string>();
string current = endID;
while (previousNodes.ContainsKey(current)) {
path.Add(current);
current = previousNodes[current];
}
path.Add(startID);
path.Reverse();
return path.ToArray();
}
}
```
使用示例:
```csharp
List<NavigationNode> nodes = new List<NavigationNode>();
nodes.Add(new NavigationNode("A", new List<string>{"B", "C"}));
nodes.Add(new NavigationNode("B", new List<string>{"A", "C", "D"}));
nodes.Add(new NavigationNode("C", new List<string>{"A", "B", "D"}));
nodes.Add(new NavigationNode("D", new List<string>{"B", "C"}));
Navigation navigation = new Navigation(nodes);
string[] path = navigation.GetClosestPath("A", "D");
foreach (string nodeID in path) {
Console.WriteLine(nodeID);
}
```