values = input() numbers = [x for x in values.split(",") if int(x)%2!=0] print (",".join(numbers)) 解读一下
时间: 2024-05-25 12:15:30 浏览: 20
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相关问题
使用列表生成式将输入以“,”为分隔符的数字字符串中的奇数提取为奇数列表,该列表中的元素为 整数,非数字字符串。例如输入为:“1,2,3,4.5,6,7,8,9”,输出为:[1,3,5,7,9]。请补充以下代码缺 失部分(1)(2)(3);输入输出格式请参看下图。(注意:不要添加额外符号,区分大小写) 请输入数字字符串:1,2,3,4,11,15 [1,3,11,15] values=input("请输入数字字符串:") numbers=【x for x in_(1)_if_(2)] answers=[(3)for x in numbers] print(answers)
请使用以下代码:
```python
values = input("请输入数字字符串:")
numbers = [int(x) for x in values.split(',') if x.isdigit() and int(x) % 2 == 1]
answers = numbers
print(answers)
```
输出为:
```python
请输入数字字符串:1,2,3,4,11,15
[1, 3, 11, 15]
```
解释:
1. 第一行代码要求用户输入数字字符串;
2. 第二行代码使用 split() 方法将字符串按照逗号分隔成列表,并使用 isdigit() 方法判断字符串是否为数字,同时判断是否为奇数,将符合条件的元素转为整数并保存在 numbers 列表中;
3. 第三行代码创建一个新的列表 answers,其中的元素为 numbers 列表中的元素;
4. 第四行代码使用 print() 函数将 answers 列表打印输出。
注意:这里不需要使用列表生成式,只需要将符合条件的元素添加到新的列表中即可。同时,使用 split() 方法可以方便地将字符串分割成列表。
Write a program to find all numbers between 'a' and 'b' (both included) such that each digit of the number is an even number, and print the results. Input There are two non-negative integers in one line: a and b Output Directly print the list
Sure, here's a Python program that will solve the problem:
```python
a, b = map(int, input().split())
# Define a function to check if a number has all even digits
def all_even_digits(n):
while n > 0:
if (n % 10) % 2 != 0:
return False
n //= 10
return True
# Loop through all numbers between a and b, check if they have all even digits, and print them if they do
for i in range(a, b+1):
if all_even_digits(i):
print(i)
```
To use this program, simply input the values of 'a' and 'b' on the first line, separated by a space. The program will then output a list of all numbers between 'a' and 'b' (inclusive) that have all even digits.