怎么用python实现五子棋游戏

五子棋游戏的实现可以分为两个部分，一个是游戏逻辑的实现，另一个是游戏界面的实现。下面是一个简单的五子棋游戏实现代码示例：

import pygame
import sys
 
# 初始化 Pygame
pygame.init()
 
# 定义游戏面板大小
WIDTH = 640
HEIGHT = 640
 
# 定义棋盘大小
BOARD_SIZE = 15
 
# 定义棋盘格子大小
GRID_SIZE = int(WIDTH / BOARD_SIZE)
 
# 定义棋子半径大小
RADIUS = int(GRID_SIZE / 2 - 2)
 
# 定义棋盘线条颜色
LINE_COLOR = (0, 0, 0)
 
# 定义黑白棋子颜色
BLACK = (0, 0, 0)
WHITE = (255, 255, 255)
 
# 创建屏幕对象
screen = pygame.display.set_mode((WIDTH, HEIGHT))
 
# 设置窗口标题
pygame.display.set_caption('五子棋')
 
# 创建棋盘
board = [[0 for x in range(BOARD_SIZE)] for y in range(BOARD_SIZE)]
 
# 定义当前下棋方
current_player = 1
 
# 绘制棋盘
def draw_board():
    for x in range(BOARD_SIZE):
        for y in range(BOARD_SIZE):
            pygame.draw.rect(screen, (255, 206, 158), (x * GRID_SIZE, y * GRID_SIZE, GRID_SIZE, GRID_SIZE))
            pygame.draw.circle(screen, LINE_COLOR, (x * GRID_SIZE + GRID_SIZE // 2, y * GRID_SIZE + GRID_SIZE // 2), RADIUS, 1)
 
# 绘制棋子
def draw_piece():
    for x in range(BOARD_SIZE):
        for y in range(BOARD_SIZE):
            if board[x][y] == 1:
                pygame.draw.circle(screen, BLACK, (x * GRID_SIZE + GRID_SIZE // 2, y * GRID_SIZE + GRID_SIZE // 2), RADIUS)
            elif board[x][y] == 2:
                pygame.draw.circle(screen, WHITE, (x * GRID_SIZE + GRID_SIZE // 2, y * GRID_SIZE + GRID_SIZE // 2), RADIUS)
 
# 判断是否胜利
def check_win(x, y, player):
    # 判断横向是否连续五个棋子
    count = 0
    for i in range(BOARD_SIZE):
        if board[i][y] == player:
            count += 1
        else:
            count = 0
        if count == 5:
            return True
 
    # 判断纵向是否连续五个棋子
    count = 0
    for j in range(BOARD_SIZE):
        if board[x][j] == player:
            count += 1
        else:
            count = 0
        if count == 5:
            return True
 
    # 判断左上到右下是否连续五个棋子
    count = 0
    for i in range(BOARD_SIZE):
        if x + i < BOARD_SIZE and y + i < BOARD_SIZE and board[x + i][y + i] == player:
            count += 1
        else:
            count = 0
        if count == 5:
            return True
 
    # 判断左下到右上是否连续五个棋子
    count = 0
    for i in range(BOARD_SIZE):
        if x + i < BOARD_SIZE and y - i >= 0 and board[x + i][y - i] == player:
            count += 1
        else:
            count = 0
        if count == 5:
            return True
 
    return False
 
# 游戏主循环
while True:
    # 处理事件
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            sys.exit()
        elif event.type == pygame.MOUSEBUTTONDOWN:
            if event.button == 1:
                # 获取鼠标点击位置
                x, y = event.pos[0] // GRID_SIZE, event.pos[1] // GRID_SIZE
 
                # 判断该位置是否已经有棋子
                if board[x][y] == 0:
                    # 在该位置下棋
                    board[x][y] = current_player
 
                    # 绘制棋子
                    draw_piece()
 
                    # 判断是否胜利
                    if check_win(x, y, current_player):
                        print('Player', current_player, 'wins!')
                        sys.exit()
 
                    # 切换下棋方
                    current_player = 3 - current_player
 
    # 绘制棋盘
    draw_board()
 
    # 刷新屏幕
    pygame.display.flip()

这个示例代码使用 Pygame 模块实现了一个简单的五子棋游戏，具体实现过程可以参考代码注释。该代码只是一个简单的示例，您可以根据自己的需求进行修改和扩展。