时间片轮转调度算法c++
时间: 2023-08-03 16:40:17 浏览: 93
好的,这是一个基于时间片轮转的简单调度算法的C++实现:
```c++
#include<iostream>
#include<queue>
using namespace std;
struct Process {
int pid;
int burst_time;
int remaining_time;
};
void time_slice_round_robin(Process processes[], int n, int time_slice) {
queue<Process> q;
int current_time = 0;
int total_burst_time = 0;
for (int i = 0; i < n; i++) {
total_burst_time += processes[i].burst_time;
processes[i].remaining_time = processes[i].burst_time;
}
while (current_time < total_burst_time) {
for (int i = 0; i < n; i++) {
if (processes[i].remaining_time > 0) {
if (processes[i].remaining_time > time_slice) {
current_time += time_slice;
processes[i].remaining_time -= time_slice;
q.push(processes[i]);
}
else {
current_time += processes[i].remaining_time;
processes[i].remaining_time = 0;
cout << "Process " << processes[i].pid << " finished at " << current_time << endl;
}
}
}
while (!q.empty()) {
Process p = q.front();
q.pop();
if (p.remaining_time > 0) {
if (p.remaining_time > time_slice) {
current_time += time_slice;
p.remaining_time -= time_slice;
q.push(p);
}
else {
current_time += p.remaining_time;
p.remaining_time = 0;
cout << "Process " << p.pid << " finished at " << current_time << endl;
}
}
}
}
}
int main() {
Process processes[] = { {1, 10}, {2, 5}, {3, 8} };
int n = sizeof(processes) / sizeof(processes[0]);
int time_slice = 2;
time_slice_round_robin(processes, n, time_slice);
return 0;
}
```
在这个实现中,我们定义了一个Process结构体表示进程,包含进程ID(pid)、进程执行时间(burst_time)和进程剩余执行时间(remaining_time)。
我们还实现了一个函数time_slice_round_robin来执行调度算法。它使用一个队列来存放当前被挂起的进程,并且在每个时间片结束时检查队列中有没有需要继续执行的进程。如果有,它会把它们放回队列中,并且继续执行下一个进程。
在main函数中,我们定义了一个包含三个进程的进程数组,并且调用time_slice_round_robin函数来执行调度算法。调度算法使用时间片大小为2。
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