编程判断输入整数的正负性和奇偶性。 **输入格式要求："%d" 提示信息："Input m:" **输出格式要求： 如果是负偶数，则输出"%d is a negative even\n" 如果是负奇数，则输出"%d is a negative odd\n" 如果是正偶数，则输出"%d is a positive even\n" 如果是正奇数，则输出"%d is a positive odd\n" 如果是0，则输出"%d is zero. It is an even\n" 程序运行示例1： Input m:6↙ 6 is a positive even 程序运行示例2： Input m:0↙ 0 is zero. It is an even

下面是C语言的实现代码：

#include <stdio.h>

int main() {
    int m;
    printf("Input m:");
    scanf("%d", &m);

    if (m == 0) {
        printf("%d is zero. It is an even\n", m);
    }
    else if (m > 0) {
        if (m % 2 == 0) {
            printf("%d is a positive even\n", m);
        }
        else {
            printf("%d is a positive odd\n", m);
        }
    }
    else {
        if (m % 2 == 0) {
            printf("%d is a negative even\n", m);
        }
        else {
            printf("%d is a negative odd\n", m);
        }
    }

    return 0;
}

程序使用了if语句进行条件判断，首先判断m是否等于0，如果是则输出"0 is zero. It is an even"。否则，再分别判断m的正负性和奇偶性。如果m为正偶数，输出"%d is a positive even"，如果m为正奇数，输出"%d is a positive odd"。如果m为负偶数，输出"%d is a negative even"，如果m为负奇数，输出"%d is a negative odd"。