The readLine method uses System.out.print (not println) to print its string argument on the screen (later when we use the readLine method, the string argument of the method will be a message telling the user to type some text). Then the readLine method uses the input scanner object to read a whole line of text from the user of the program and returns the text as result.java代码

时间: 2024-02-07 20:04:10 浏览: 22
Sure, here is an example of how to implement the readLine method in the CLI class: ```java private static String readLine(String message) { System.out.print(message + " "); return input.nextLine(); } ``` This method takes a string argument called "message", which is the message that will be displayed to the user asking them to type some text. It then uses System.out.print to display the message on the screen without adding a newline character. Finally, it returns the text entered by the user using the input scanner object's nextLine() method. You can then call this method in your program like this: ```java String name = readLine("Please enter your name:"); System.out.println("Hello, " + name + "!"); ``` This will display the message "Please enter your name:" on the screen, wait for the user to enter some text, and then store the entered text in the "name" variable. The program will then display the message "Hello, [name]!" where [name] is the value entered by the user.

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The readPosInt method uses System.out.print (not println) to print its string argument on the screen (later when we use the readPosInt method, the string argument of the method will be a message telling the user to type some integer). Then the readPosInt method uses the input scanner object to read an integer from the user of the program. After reading the integer, the readPosInt method must also use the scanner’s nextLine method to read the single newline character that comes from the user pressing the Enter key on the keyboard after typing the integer (if you do not read this newline character using the nextLine method inside the readPosInt method, then the newline character will remain in the input stream, and, the next time you use the readLine method described above, the readLine method will just immediately read only the newline character from the input stream and return an empty string as result, without waiting for the user to type anything!) If the user types something which is not an integer, then the nextInt method of the scanner will throw an InputMismatchException. In that case the code of your readPosInt method must catch the exception, use System.out.println to print the error message "You must type an integer!" to the user (use System.out.println for this, not System.err.println, otherwise you might hit a bug in Eclipse...), use the scanner’s nextLine method to read (and ignore) the wrong input typed by the user of the program (if you do not do this, the wrong input typed by the user will remain in the input stream, and the next time you call the nextInt method again, you will get an InputMismatchException again!), and then do the whole thing again (including printing again the string argument of the readPosInt method) to try to read an integer again (hint: put the whole code of the method inside a while loop). After reading the integer and the newline character (which is just ignored), the readPosInt method tests the integer.写java文件

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