编写程序计算sn=1+1/2+1/3+1/4+1/5

Sure, the program to calculate sn=1 1/2 1/3 1/4 1/5 is quite simple. Here's a Python code snippet that computes sn.

n = 5
sum_numbers = 0.0

for i in range(1, n+1):
  sum_numbers += 1/i

print(sum_numbers)

The output will be 2.283333333333333.

相关问题

编写c语言程序计算sn=1+1/2+1/3+1/4+1/5

好的，这个问题非常简单。以下是C语言程序：

#include <stdio.h>
int main() {
int n=5;
float sum=0;
for(int i=1;i<=n;i++){
sum+=1.0/i;
}
printf("The sum of the series is %f",sum);
return 0;
}

程序输出：The sum of the series is 2.283333。希望对您有帮助！

编写程序计算sn=1+1/2+1/3....+1/n

以下是C语言实现计算Sn的程序：

#include <stdio.h>

double fun(int n) {
    double sn = 0.0;
    int i;
    for (i = 1; i <= n; i++) {
        sn += 1.0 / i;
    }
    return sn;
}

int main() {
    int n = 15;
    double sum = fun(n);
    printf("sum is %f\n", sum);
    return 0;
}

运行结果：

sum is 3.318228