python编写程序计算sn=1+1/2+1/3....+1/n
时间: 2023-11-19 19:05:51 浏览: 89
以下是两种Python编写程序计算sn=1+1/2+1/3....+1/n的方法:
方法一:使用循环累加
```python
def calc_sn(n):
s = 0
for i in range(1, n+1):
s += 1/i
return s
if __name__ == '__main__':
n = int(input("请输入n的值:"))
sn = calc_sn(n)
print("sn的值为:", sn)
```
方法二:使用递归
```python
def calc_sn(n):
if n == 1:
return 1
else:
return 1/n + calc_sn(n-1)
if __name__ == '__main__':
n = int(input("请输入n的值:"))
sn = calc_sn(n)
print("sn的值为:", sn)
```
相关问题
python编写程序计算sn=1+1/2+1/3....+1/n,输出结果保留两位小数
以下是Python编写程序计算Sn=1+1/2+1/3+...+1/n,输出结果保留两位小数的例子:
```python
n = int(input('请输入n的值:'))
sum1 = 0
for i in range(1, n + 1):
sum1 += 1 / i
print(f'Sn={sum1:.2f}')
```
编写程序计算sn=1+1/2+1/3+1/4+1/5
Sure, the program to calculate sn=1 1/2 1/3 1/4 1/5 is quite simple. Here's a Python code snippet that computes sn.
```
n = 5
sum_numbers = 0.0
for i in range(1, n+1):
sum_numbers += 1/i
print(sum_numbers)
```
The output will be 2.283333333333333.