写一个退箱子程序要求只有三次机会
时间: 2023-09-06 15:08:41 浏览: 52
好的,以下是一个简单的退箱子程序,要求只有三次机会:
```
box_num = input("请输入要退的箱子编号:")
chance = 3
while chance > 0:
if box_num == "12345":
print("箱子已退回,谢谢!")
break
else:
chance -= 1
if chance == 0:
print("您的机会已用完,无法继续退箱子。")
else:
print("箱子编号错误,请重新输入。您还有%d次机会。" % chance)
box_num = input("请输入要退的箱子编号:")
```
程序中,首先要求用户输入要退的箱子编号。然后,使用一个 `while` 循环来判断用户的输入是否正确。如果用户输入的箱子编号是正确的(这里示例中假设正确的箱子编号是 "12345"),则输出退箱成功的信息并结束循环。如果用户输入的箱子编号不正确,则将剩余机会减一,并输出相应的提示信息。如果用户已经用完了三次机会仍然没有输入正确的箱子编号,则输出机会用完的信息并结束循环。
注意,这只是一个简单的示例程序,实际情况中可能需要更多的输入验证和错误处理。
相关问题
用c语言写一个推箱子程序
推箱子是一种经典的益智游戏,可以用C语言实现。下面是一个简单的推箱子程序实现:
```c
#include <stdio.h>
#define MAX_ROW 10
#define MAX_COL 10
int map[MAX_ROW][MAX_COL] = {
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
{1, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{1, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{1, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{1, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{1, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{1, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{1, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{1, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
}; // 地图,1表示墙,0表示空地,X表示箱子,P表示人
int row = 1, col = 1; // 人所在的位置,初始在(1,1)
void print_map() {
int i, j;
for (i = 0; i < MAX_ROW; i++) {
for (j = 0; j < MAX_COL; j++) {
if (map[i][j] == 1) {
printf("#");
} else if (i == row && j == col) {
printf("P");
} else if (map[i][j] == 2) {
printf("X");
} else {
printf(" ");
}
}
printf("\n");
}
}
int main() {
int i, j;
// 找到箱子和人的初始位置
for (i = 0; i < MAX_ROW; i++) {
for (j = 0; j < MAX_COL; j++) {
if (map[i][j] == 'P') {
row = i;
col = j;
}
}
}
while (1) {
system("clear"); // 清屏
print_map(); // 打印地图
// 判断是否胜利
int win = 1;
for (i = 0; i < MAX_ROW; i++) {
for (j = 0; j < MAX_COL; j++) {
if (map[i][j] == 'X') {
win = 0;
}
}
}
if (win) {
printf("You win!\n");
break;
}
char input;
printf("Please enter a direction (w/s/a/d): ");
scanf("%c", &input);
int new_row = row, new_col = col;
switch (input) {
case 'w': new_row--; break;
case 's': new_row++; break;
case 'a': new_col--; break;
case 'd': new_col++; break;
}
if (map[new_row][new_col] == 0) { // 空地
row = new_row;
col = new_col;
} else if (map[new_row][new_col] == 'X') { // 箱子
int new_box_row = new_row, new_box_col = new_col;
switch (input) {
case 'w': new_box_row--; break;
case 's': new_box_row++; break;
case 'a': new_box_col--; break;
case 'd': new_box_col++; break;
}
if (map[new_box_row][new_box_col] == 0) { // 箱子前面是空地
map[new_box_row][new_box_col] = 'X';
map[new_row][new_col] = 0;
row = new_row;
col = new_col;
}
}
getchar(); // 读取多余的回车
}
return 0;
}
```
这个程序有一个简单的地图,可以用w、s、a、d键控制人物的移动,将箱子推到指定位置即可获胜。该程序可以在Linux终端中运行,使用system("clear")清屏。
写一个推箱子python程序
当然,我可以帮您写一个推箱子的Python程序。以下是一个基本的推箱子游戏示例:
```python
# 定义地图
MAP = [
"#####",
"# #",
"# #",
"#o #",
"#####"
]
# 将地图转换为二维列表
map_list = [list(row) for row in MAP]
# 定义玩家的初始位置
player_x, player_y = 3, 1
# 定义箱子的初始位置
box_x, box_y = 3, 2
# 游戏循环
while True:
# 打印地图
for row in map_list:
print("".join(row))
# 判断是否通关
if map_list[1][3] == "o" and map_list[2][3] == "o":
print("你通关了!")
break
# 获取玩家输入
move = input("移动方向(上:w,下:s,左:a,右:d):")
# 移动箱子
if move == "w" and box_x == player_x - 1 and map_list[box_y - 1][box_x] == " ":
map_list[box_y][box_x], map_list[box_y - 1][box_x] = " ", "o"
box_y -= 1
elif move == "s" and box_x == player_x + 1 and map_list[box_y + 1][box_x] == " ":
map_list[box_y][box_x], map_list[box_y + 1][box_x] = " ", "o"
box_y += 1
elif move == "a" and box_y == player_y - 1 and map_list[box_y][box_x - 1] == " ":
map_list[box_y][box_x], map_list[box_y][box_x - 1] = " ", "o"
box_x -= 1
elif move == "d" and box_y == player_y + 1 and map_list[box_y][box_x + 1] == " ":
map_list[box_y][box_x], map_list[box_y][box_x + 1] = " ", "o"
box_x += 1
# 移动玩家
elif move == "w" and map_list[player_y - 1][player_x] == " ":
map_list[player_y][player_x], map_list[player_y - 1][player_x] = " ", "@"
player_y -= 1
elif move == "s" and map_list[player_y + 1][player_x] == " ":
map_list[player_y][player_x], map_list[player_y + 1][player_x] = " ", "@"
player_y += 1
elif move == "a" and map_list[player_y][player_x - 1] == " ":
map_list[player_y][player_x], map_list[player_y][player_x - 1] = " ", "@"
player_x -= 1
elif move == "d" and map_list[player_y][player_x + 1] == " ":
map_list[player_y][player_x], map_list[player_y][player_x + 1] = " ", "@"
player_x +=