IFNULL(_receipt_all.yyyy,YEAR (NOW()))yyyy,

时间: 2023-11-01 12:07:52 浏览: 34
这是一个SQL语句中的表达式,大致的意思是:如果_receipt_all表中的yyyy列不为空,则返回yyyy列的值,否则返回当前时间的年份。 具体解释如下: - IFNULL(expr1, expr2) 函数:如果expr1不为NULL,则返回expr1的值,否则返回expr2的值。 - _receipt_all.yyyy:表示_receipt_all表中的yyyy列。 - YEAR(NOW()):是MySQL中的一个内置函数,用于返回当前时间的年份。 因此,IFNULL(_receipt_all.yyyy,YEAR (NOW()))的含义是,如果_receipt_all表中yyyy列不为空,则返回yyyy列的值,否则返回当前时间的年份。最后加上"yyyy",表示将结果命名为"yyyy"。
相关问题

IFNULL( sum(_receipt_all.amount), 0 ) amount

这是一个SQL语句中的表达式,大致的意思是:如果_receipt_all表中的amount列的和不为NULL,则返回amount列的和,否则返回0。 具体解释如下: - IFNULL(expr1, expr2) 函数:如果expr1不为NULL,则返回expr1的值,否则返回expr2的值。 - SUM(expr) 函数:是MySQL中的一个聚合函数,用于计算指定列的总和。 - _receipt_all.amount:表示_receipt_all表中的amount列。 - 0:表示当_receipt_all表中的amount列的和为NULL时,返回的默认值。 因此,IFNULL(sum(_receipt_all.amount), 0)的含义是,如果_receipt_all表中amount列的和不为NULL,则返回amount列的和,否则返回0。最后加上"amount",表示将结果命名为"amount"。

优化以下SQL select pao.id, pao.order_no, pao.apply_time, pao.purchase_user_id, pao.purchase_user_name, pao.apply_user_id, pao.apply_user_name, pao.apply_department_id, pao.apply_department_name, pao.apply_end_time, pao.create_user_id, pao.create_user_name, pao.approve_type, pao.approve_user_id, pao.approve_user_name, pao.approve_time, pao.description, pao.order_type, pao.purchase_type, pao.storage_type, pao.compose_order_no, pao.company_id, pao.delete, pao.create_time, pao.update_time, pao.supplier_id, pao.image_path, pao.contract_id, pao.status, pao.invoice_signer_name, pao.total_amount, pao.total_amount_tax, pao.purchase_status, pao.cancel_reason, pao.print_status, pao.demand_id, pao.arrival_status, pao.supervise_num, pao.supervise_date, pao.merge_apply_id, pao.deadline, pao.remind , s.name as supplierName, paod.amount, cm.return_status as returnStatus, cm.inventory_status as inventoryStatus, cm.stock_remark, cm.merge_flag, cm.signature_file, cm.department_pass, cm.receipt_file, cm.amount_paid, cm.amount_unpaid, cm.contract_name, cm.status as contractStatus, cm.contract_no, cm.contract_amount, paod.product_name, cm.advance_payment, cm.advance_ratio, cm.currency_unit from purchase_apply_order pao left join supplier s on pao.supplier_id = s.id left join ( SELECT GROUP_CONCAT(distinct p.product_name) product_name, sum(IFNULL(amount_tax, 0)) amount, apply_order_no from purchase_apply_order_details pa left join product p on p.pn_code = pa.product_code where p.company_id = 29 GROUP BY apply_order_no ) paod on paod.apply_order_no = pao.order_no left join contract_management cm on pao.contract_id = cm.id where pao.delete = 0 and pao.company_id = 29 and deadline <= '2023-05-25 15:34:00.01' and remind = 0 and arrival_status in( 0 , 1 ) order by pao.create_time desc;

首先,我们可以对该 SQL 查询语句进行简化,只选择需要的字段而不是全部选择。其次,我们可以尝试添加索引以加快查询速度。 以下是优化后的 SQL 查询语句: ``` SELECT pao.id, pao.order_no, pao.apply_time, pao.purchase_user_id, pao.purchase_user_name, pao.apply_user_id, pao.apply_user_name, pao.apply_department_id, pao.apply_department_name, pao.apply_end_time, pao.create_user_id, pao.create_user_name, pao.approve_type, pao.approve_user_id, pao.approve_user_name, pao.approve_time, pao.description, pao.order_type, pao.purchase_type, pao.storage_type, pao.compose_order_no, pao.company_id, pao.delete, pao.create_time, pao.update_time, pao.supplier_id, pao.image_path, pao.contract_id, pao.status, pao.invoice_signer_name, pao.total_amount, pao.total_amount_tax, pao.purchase_status, pao.cancel_reason, pao.print_status, pao.demand_id, pao.arrival_status, pao.supervise_num, pao.supervise_date, pao.merge_apply_id, pao.deadline, pao.remind, s.name AS supplierName, paod.amount, cm.return_status AS returnStatus, cm.inventory_status AS inventoryStatus, cm.stock_remark, cm.merge_flag, cm.signature_file, cm.department_pass, cm.receipt_file, cm.amount_paid, cm.amount_unpaid, cm.contract_name, cm.status AS contractStatus, cm.contract_no, cm.contract_amount, paod.product_name, cm.advance_payment, cm.advance_ratio, cm.currency_unit FROM purchase_apply_order pao LEFT JOIN supplier s ON pao.supplier_id = s.id LEFT JOIN ( SELECT GROUP_CONCAT(DISTINCT p.product_name) product_name, SUM(IFNULL(amount_tax, 0)) amount, apply_order_no FROM purchase_apply_order_details pa LEFT JOIN product p ON p.pn_code = pa.product_code WHERE p.company_id = 29 GROUP BY apply_order_no ) paod ON paod.apply_order_no = pao.order_no LEFT JOIN contract_management cm ON pao.contract_id = cm.id WHERE pao.delete = 0 AND pao.company_id = 29 AND deadline <= '2023-05-25 15:34:00.01' AND remind = 0 AND arrival_status IN (0, 1) ORDER BY pao.create_time DESC; ``` 我们可以为 `purchase_apply_order` 表的 `company_id` 字段和 `deadline` 字段以及 `remind` 字段创建索引。同时,也可以为 `arrival_status` 字段和 `delete` 字段创建索引。这可以大大加快查询速度。 ``` CREATE INDEX idx_purchase_apply_order_company_id_deadline_remind ON purchase_apply_order (company_id, deadline, remind); CREATE INDEX idx_purchase_apply_order_arrival_status_delete ON purchase_apply_order (arrival_status, delete); ```

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SELECT t1.supplier_id, t1.ky_count, t1.ky_amount, IFNULL(t2.ky_refund_count,0) as ky_refund_count, IFNULL(t2.ky_refund_amount,0) as ky_refund_amount FROM ( SELECT a.supplier_id, count( DISTINCT c.order_no ) AS ky_count, SUM( IFNULL( c.record_amount, 0 )) / 100 AS ky_amount FROM settle_order a INNER JOIN settle_order_receipt b ON a.order_id = b.order_id INNER JOIN cash_withdrawal_record c ON b.third_trade_no = c.order_no WHERE a.is_del = 0 AND a.order_time >= '2023-05-28 00:00:00' AND a.order_time < '2023-05-29 00:00:00' AND a.order_type in (70,75) AND a.supplier_id IN (78,63,58,57,64,72,71,74,83,77,70,69,67,82,65,87,73,59,66,60,86,85,79,80,84,90) AND b.channel_code = 61 AND c.con_bank_account_no IN ( 247, 325 ) AND c.record_status = 1 AND c.record_time > '2023-05-01 00:00:00' GROUP BY a.supplier_id ) t1 LEFT JOIN ( SELECT a.supplier_id, count( DISTINCT b.order_no ) AS ky_refund_count, SUM( IFNULL( b.record_amount, 0 )) / 100 AS ky_refund_amount FROM settle_order_refund a INNER JOIN cash_withdrawal_record b ON a.third_refund_id = b.order_no WHERE a.is_del = 0 AND a.order_type in (70,75) AND a.apply_time >= '2023-05-28 00:00:00' AND a.apply_time < '2023-05-29 00:00:00' AND a.supplier_id IN (78,63,58,57,64,72,71,74,83,77,70,69,67,82,65,87,73,59,66,60,86,85,79,80,84,90) AND a.channel_code = 61 AND b.con_bank_account_no IN ( 247, 325 ) AND b.record_status = 5 AND b.record_time > '2023-05-01 00:00:00' GROUP BY a.supplier_id ) t2 ON t1.supplier_id = t2.supplier_id order by t1.supplier_id asc

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