def meanshift(data, r): labels = np.zeros(len(data.T)) peaks = [] #聚集的类中心 label_no = 1 #当前label labels[0] = label_no # findpeak is called for the first index out of the loop peak = findpeak(data, 0, r) peakT = np.concatenate(peak, axis=0).T peaks.append(peakT) # Every data point is iterated through for idx in range(1, len(data.T)): # 遍历数据,寻找当前点的peak # 并实时关注当前peak是否会收敛到一个新的聚类(和已有peaks比较) # 若是,更新label_no,peaks,labels,继续 # 若不是,当前点就属于已有类,继续 ### YOUR CODE HERE
时间: 2024-02-14 16:36:01 浏览: 55
### 以下是完整的 Python 代码实现
def meanshift(data, r):
labels = np.zeros(len(data.T))
peaks = [] #聚集的类中心
label_no = 1 #当前label
labels[0] = label_no
# findpeak is called for the first index out of the loop
peak = findpeak(data, 0, r)
peakT = np.concatenate(peak, axis=0).T
peaks.append(peakT)
# Every data point is iterated through
for idx in range(1, len(data.T)):
# 遍历数据,寻找当前点的peak
peak = findpeak(data, idx, r)
peakT = np.concatenate(peak, axis=0).T
# 实时关注当前peak是否会收敛到一个新的聚类(和已有peaks比较)
found_peak = False
for i in range(len(peaks)):
# 如果当前peak已经属于一个已有聚类,就将当前点分配到该聚类
if np.linalg.norm(peakT - peaks[i]) < r:
labels[idx] = i+1
found_peak = True
break
# 如果当前peak没有收敛到任何一个已有聚类,就创建新的聚类并将当前点分配到该聚类
if not found_peak:
label_no += 1
peaks.append(peakT)
labels[idx] = label_no
return labels
### 该函数实现了 Mean Shift 算法中的聚类过程,其中 data 是输入的数据矩阵,r 是半径参数。该函数返回一个标签向量,表示每个数据点所属的聚类编号。
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