降低这段代码的重复率：def checkTimeWindow(route,model,vehicle): timetable=[] departure=0 for i in range(len(route)): if i == 0: next_node_id = route[i + 1] travel_time = int(model.distance_matrix[vehicle.type, next_node_id] /vehicle.free_speed) departure = max(0, model.demand_dict[next_node_id].start_time - travel_time) timetable.append((int(departure), int(departure))) elif 1 <= i <= len(route) - 2: last_node_id = route[i - 1] current_node_id = route[i] current_node = model.demand_dict[current_node_id] travel_time = int(model.distance_matrix[last_node_id, current_node_id] / vehicle.free_speed) arrival = max(timetable[-1][1] + travel_time, current_node.start_time) departure = arrival + current_node.service_time timetable.append((int(arrival), int(departure))) if departure > current_node.end_time: departure = float('inf') break else: last_node_id = route[i - 1] travel_time = int(model.distance_matrix[last_node_id, vehicle.type] / vehicle.free_speed) departure = timetable[-1][1] + travel_time timetable.append((int(departure), int(departure))) if departure<vehicle.end_time: return True else: return False

可以将重复的代码提取出来，封装成一个函数，如下所示：

def get_travel_time(model, vehicle, start_node_id, end_node_id):
    return int(model.distance_matrix[start_node_id, end_node_id] / vehicle.free_speed)

def checkTimeWindow(route, model, vehicle):
    timetable = []
    departure = 0
    
    for i, node_id in enumerate(route):
        if i == 0:
            next_node_id = route[i + 1]
            travel_time = get_travel_time(model, vehicle, vehicle.type, next_node_id)
            departure = max(0, model.demand_dict[next_node_id].start_time - travel_time)
            timetable.append((int(departure), int(departure)))
        
        elif 1 <= i <= len(route) - 2:
            last_node_id = route[i - 1]
            current_node = model.demand_dict[node_id]
            travel_time = get_travel_time(model, vehicle, last_node_id, node_id)
            arrival = max(timetable[-1][1] + travel_time, current_node.start_time)
            departure = arrival + current_node.service_time
            timetable.append((int(arrival), int(departure)))
            
            if departure > current_node.end_time:
                departure = float('inf')
                break
        
        else:
            last_node_id = route[i - 1]
            travel_time = get_travel_time(model, vehicle, last_node_id, vehicle.type)
            departure = timetable[-1][1] + travel_time
            timetable.append((int(departure), int(departure)))
        
        if departure >= vehicle.end_time:
            return False
    
    return True

这样，代码中的重复率就降低了。