linux简易扫雷c语言代码,C语言实现简易版扫雷的完整过程

以下是一个简单的基于Linux的扫雷游戏C语言代码。代码实现了一个简单的扫雷游戏，玩家可以选择不同的难度级别并尝试找到所有地雷。

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define ROW 10
#define COL 10
#define EASY 10
#define MEDIUM 20
#define HARD 30

int main()
{
    int board[ROW][COL], num_mines, num_flags;
    int i, j, r, c, count, gameover = 0, win = 0, choice;
    char action;
    srand(time(NULL));
    printf("Welcome to Minesweeper\n");
    printf("----------------------\n");
    printf("Choose a difficulty level:\n");
    printf("1. Easy\n2. Medium\n3. Hard\n");
    scanf("%d", &choice);
    switch (choice) {
        case 1:
            num_mines = EASY;
            break;
        case 2:
            num_mines = MEDIUM;
            break;
        case 3:
            num_mines = HARD;
            break;
        default:
            printf("Invalid choice. Defaulting to Easy difficulty.\n");
            num_mines = EASY;
            break;
    }
    //initialize board with 0's
    for (i = 0; i < ROW; i++) {
        for (j = 0; j < COL; j++) {
            board[i][j] = 0;
        }
    }
    //place mines randomly
    for (i = 0; i < num_mines; i++) {
        r = rand() % ROW;
        c = rand() % COL;
        if (board[r][c] == -1) { //already a mine here
            i--;
            continue;
        }
        board[r][c] = -1;
    }
    //fill in numbers
    for (i = 0; i < ROW; i++) {
        for (j = 0; j < COL; j++) {
            if (board[i][j] == -1) { //skip mines
                continue;
            }
            count = 0;
            if (i-1 >= 0 && j-1 >= 0 && board[i-1][j-1] == -1) count++;
            if (i-1 >= 0 && board[i-1][j] == -1) count++;
            if (i-1 >= 0 && j+1 < COL && board[i-1][j+1] == -1) count++;
            if (j-1 >= 0 && board[i][j-1] == -1) count++;
            if (j+1 < COL && board[i][j+1] == -1) count++;
            if (i+1 < ROW && j-1 >= 0 && board[i+1][j-1] == -1) count++;
            if (i+1 < ROW && board[i+1][j] == -1) count++;
            if (i+1 < ROW && j+1 < COL && board[i+1][j+1] == -1) count++;
            board[i][j] = count;
        }
    }

    //game loop
    while (!gameover && !win) {
        num_flags = 0;
        printf("\n\n");
        for (i = 0; i < ROW; i++) {
            printf("%d ", i);
            for (j = 0; j < COL; j++) {
                if (board[i][j] == -2) { //flag
                    printf("F ");
                    num_flags++;
                }
                else if (board[i][j] >= 0 && board[i][j] <= 8) {
                    printf("%d ", board[i][j]);
                }
                else {
                    printf("X ");
                }
            }
            printf("\n");
        }
        printf("  ");
        for (i = 0; i < COL; i++) {
            printf("%d ", i);
        }
        printf("\n\n");
        printf("Number of flags: %d\n", num_flags);
        printf("Enter coordinate and action (f = flag, u = unflag, r = reveal): ");
        scanf("%d %d %c", &r, &c, &action);
        if (r < 0 || r >= ROW || c < 0 || c >= COL) {
            printf("Invalid coordinate.\n");
            continue;
        }
        if (action == 'f' || action == 'F') { //flag
            if (board[r][c] != -2) {
                board[r][c] = -2;
            }
            else {
                board[r][c] = 0;
            }
        }
        else if (action == 'r' || action == 'R') { //reveal
            if (board[r][c] == -1) { //mine
                gameover = 1;
            }
            else {
                board[r][c] += 10; //reveal
                if (board[r][c] == 9) { //win
                    win = 1;
                }
                else if (board[r][c] == 10) { //empty square
                    //reveal adjacent squares
                    if (r-1 >= 0 && c-1 >= 0 && board[r-1][c-1] >= 0 && board[r-1][c-1] <= 8) board[r-1][c-1] += 10;
                    if (r-1 >= 0 && board[r-1][c] >= 0 && board[r-1][c] <= 8) board[r-1][c] += 10;
                    if (r-1 >= 0 && c+1 < COL && board[r-1][c+1] >= 0 && board[r-1][c+1] <= 8) board[r-1][c+1] += 10;
                    if (c-1 >= 0 && board[r][c-1] >= 0 && board[r][c-1] <= 8) board[r][c-1] += 10;
                    if (c+1 < COL && board[r][c+1] >= 0 && board[r][c+1] <= 8) board[r][c+1] += 10;
                    if (r+1 < ROW && c-1 >= 0 && board[r+1][c-1] >= 0 && board[r+1][c-1] <= 8) board[r+1][c-1] += 10;
                    if (r+1 < ROW && board[r+1][c] >= 0 && board[r+1][c] <= 8) board[r+1][c] += 10;
                    if (r+1 < ROW && c+1 < COL && board[r+1][c+1] >= 0 && board[r+1][c+1] <= 8) board[r+1][c+1] += 10;
                }
            }
        }
        else if (action == 'u' || action == 'U') { //unflag
            if (board[r][c] == -2) {
                board[r][c] = 0;
            }
        }
        else {
            printf("Invalid action.\n");
        }
    }

    //game over, reveal all squares
    printf("\n\n");
    for (i = 0; i < ROW; i++) {
        printf("%d ", i);
        for (j = 0; j < COL; j++) {
            if (board[i][j] == -2) { //flag
                printf("F ");
            }
            else if (board[i][j] >= 0 && board[i][j] <= 8) {
                printf("%d ", board[i][j]);
            }
            else if (board[i][j] == -1) { //mine
                printf("M ");
            }
            else {
                printf("X ");
            }
        }
        printf("\n");
    }
    printf("  ");
    for (i = 0; i < COL; i++) {
        printf("%d ", i);
    }
    printf("\n\n");
    if (gameover) {
        printf("Game over! You hit a mine.\n");
    }
    else {
        printf("Congratulations, you win!\n");
    }
    
    return 0;
}

该代码包括以下功能：

- 难度选择
- 地雷随机放置
- 数字填充
- 可以插旗
- 可以取消插旗
- 可以揭开方块
- 只有揭开所有非地雷方块才能获胜

这个代码还有可以改进的地方，比如增加计时器和玩家得分等等。但是，希望这个代码可以给你提供一个基础的思路和参考。