Create a list of years that appear on both the top_critic_years_more_than_four_games table and the top_user_years_more_than_four_games table. -- Select the year results that appear on both tables
时间: 2024-01-14 11:03:55 浏览: 21
Sure, here's the SQL query to create a list of years that appear on both the top_critic_years_more_than_four_games table and the top_user_years_more_than_four_games table:
```
SELECT year
FROM top_critic_years_more_than_four_games
WHERE year IN (
SELECT year
FROM top_user_years_more_than_four_games
);
```
This query uses a subquery to select the years that appear in both tables, and then returns the list of years that meet this condition. Let me know if you have any other questions!
相关问题
column "b.host_port" must appear in the GROUP BY clause or be used in an aggregate function
这个错误通常在使用 GROUP BY 子句时出现,提示你的查询语句中存在一个或多个列没有包含在 GROUP BY 子句中,也没有使用聚合函数进行处理。
例如,假设我们有一个名为 table1 的表,其中包含名称(name)、地址(address)和年龄(age)等列。如果我们要按照地址分组,并计算每个地址的平均年龄,可以使用以下查询语句:
```
SELECT address, AVG(age) FROM table1 GROUP BY address;
```
这个查询语句将会按照地址分组,并计算每个地址的平均年龄,返回结果如下:
```
+-----------------+------------------+
| address | avg(age) |
+-----------------+------------------+
| address1 | 28.5 |
| address2 | 32.0 |
| address3 | 26.0 |
+-----------------+------------------+
```
如果我们尝试添加一个额外的列 b.host_port,查询语句将会变成:
```
SELECT address, b.host_port, AVG(age) FROM table1 GROUP BY address;
```
这个查询语句将会查询每个地址、每个 host_port 的平均年龄,但是因为 host_port 列没有被包含在 GROUP BY 子句中,也没有使用聚合函数进行处理,所以会导致错误提示:column "b.host_port" must appear in the GROUP BY clause or be used in an aggregate function。
为了解决这个问题,我们需要将查询语句修改为:
```
SELECT address, b.host_port, AVG(age) FROM table1 GROUP BY address, b.host_port;
```
这个查询语句将会查询每个地址、每个 host_port 的平均年龄,并且将 address 和 host_port 两列都包含在了 GROUP BY 子句中,这样就不会再出现错误提示了。
column "b.person_name" must appear in the GROUP BY clause or be used in an aggregate function
这个错误意味着你在一个查询中使用了 GROUP BY 子句,但是列 "b.person_name" 没有在 GROUP BY 子句中出现,也没有被用于聚合函数。在 GROUP BY 子句中,你需要指定所有不在聚合函数中的列。
要解决这个问题,你可以将列 "b.person_name" 添加到 GROUP BY 子句中,或者在 SELECT 子句中使用聚合函数来处理它。例如,你可以这样修改查询:
SELECT b.person_name, COUNT(b.id)
FROM table_name b
GROUP BY b.person_name;
这样做将以 "person_name" 为分组依据,并计算每个组中的记录数量。请根据你的具体需求适当调整查询语句。