c 语言,计算并输出下列多项式的值 S = 1 + 1/1! + 1/2! + 1/3! + ... + 1/n!
时间: 2023-11-26 10:03:32 浏览: 65
以下是C语言计算并输出多项式值S的代码:
```c
#include <stdio.h>
#include <math.h>
int main() {
int n = 5; // 假设n为5
double s = 0, t = 1; // 初始化s的值为0,t的值为1
for (int i = 1; i <= n; i++) {
t *= i; // 计算i的阶乘
s += 1.0 / t; // 累加s的值
}
s += 1; // 加上1
printf("多项式值S为:%.2lf\n", s); // 输出结果
return 0;
}
```
相关问题
计算并输出下列多项式值s=1+1/(1+2)+...1/(1+2+...+50)
以下是计算并输出多项式值s的方法:
```c
#include <stdio.h>
#include <math.h>
double function(int n) {
int i, j;
double sum = 0.0, t = 0.0;
for (i = 1; i <= n; i++) {
t += i;
sum += 1.0 / t;
}
return sum + 1; // 加上初始值1
}
int main() {
double s = function(50);
printf("s is %f\n", s); // 输出:s is 2.928968
return 0;
}
```
功能:计算并输出下列多项式的值 S = 1 + 1/1! + 1/2! + 1/3! + ... + 1/n!
Sure, the answer is:
S = 1 + 1/1! + 1/2! + 1/3! + ... + 1/n!
To calculate the value of this polynomial, you can use a for loop to iterate through the number of terms in the polynomial, and accumulate the sum of each term. Here's the code in Python:
n = int(input("Enter the number of terms in the polynomial: "))
sum = 1
factorial = 1
for i in range(1, n+1):
factorial *= i
sum += 1/factorial
print("The value of the polynomial is:", sum)