subdir in cancer_subdirs
时间: 2024-04-24 14:18:40 浏览: 12
以下是一个示例代码,用于判断子文件夹是否存在于给定的文件夹中[^1]:
```python
def subdirs(folder, join=True, prefix=None, suffix=None, sort=True):
if join:
l = os.path.join
else:
l = lambda x, y: y
res = [l(folder, i) for i in os.listdir(folder) if os.path.isdir(os.path.join(folder, i)) and (prefix is None or i.startswith(prefix)) and (suffix is None or i.endswith(suffix))]
if sort:
res.sort()
return res
cancer_subdirs = subdirs('/path/to/folder', prefix='cancer')
subdir = 'subfolder_name'
if subdir in cancer_subdirs:
print(f"{subdir} exists in cancer_subdirs")
else:
print(f"{subdir} does not exist in cancer_subdirs")
```
请注意,您需要将`/path/to/folder`替换为实际的文件夹路径,并将`subfolder_name`替换为要检查的子文件夹名称。