java实现五子棋获胜的方法

在Java中实现五子棋游戏，判断是否获胜通常会检查以下几个条件：

1. **横线判断**：检查一行、一列或一条对角线上是否有五个连续的同色棋子。

public boolean checkWin(int[][] board, char player) {
    for (int i = 0; i < BOARD_SIZE; i++) {
        // 检查行
        if (board[i][0] == player && board[i][1] == player && board[i][2] == player && board[i][3] == player && board[i][4] == player)
            return true;
        
        // 检查列
        if (board[0][i] == player && board[1][i] == player && board[2][i] == player && board[3][i] == player && board[4][i] == player)
            return true;

        // 检查左上到右下的对角线
        if (board[0][0] == player && board[1][1] == player && board[2][2] == player && board[3][3] == player && board[4][4] == player)
            return true;

        // 检查左下到右上的对角线
        if (board[0][4] == player && board[1][3] == player && board[2][2] == player && board[3][1] == player && board[4][0] == player)
            return true;
    }
    return false;
}

2. **边界延伸判断**：如果棋子位于边缘，可以延伸边界来检查是否存在获胜情况。

上述代码只是一个基本的胜利检查方法，实际应用中可能还需要考虑其他特殊情况，如游戏结束状态、空位等等。同时，五子棋还有连珠规则，即禁手，这需要额外的规则检查。